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Goryan [66]
3 years ago
5

A tennis ball "A" is released from rest down a 10.0 m long inclined ramp with a uniform acceleration of 5.0 m/s2 . Another tenni

s ball "B" is initially located at the same height as ball "A" right above the lower edge of the ramp. Ball "B" is thrown upward with some initial speed at the same instant as the release of ball "A". A) What was the initial velocity of ball "B" so that "A" and "B" reach the bottom of the ramp at the same time?
Physics
1 answer:
Naya [18.7K]3 years ago
6 0

Answer:

4.8 m/s

Explanation:

For tennis ball "A", we are told that;

Initial velocity; u = 0 m/s

Distance; h = 10 m

Acceleration; a = 5 m/s²

Thus, using Newton's equation of motion, we can find time(t).

h = ut + ½at²

10 = 0 + ½(5)t²

10 = ½(5t²)

t² = 2 × 10/5

t² = 4

t = √4

t = 2 seconds

Now, this time would be the same for ball B since we are told that they reach the bottom at the same time.

Now, since ball B is thrown upwards, it means it is thrown against gravity. Thus;

h = -ut + ½gt²

10 = -2u + ½(9.8)(2²)

Where u is initial velocity of Ball B.

Thus;

10 = -2u + 19.6

2u = 19.6 - 10

2u = 9.6

u = 9.6/2

u = 4.8 m/s

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Assuming both graduated cylinders are holding water at room temperature, which cylinder has more thermal energy?
natta225 [31]

Answer:

The correct option is;

The graduate cylinder with more water has more thermal energy because it is holding more water molecules

Explanation:

Given that the thermal energy of the system is the energy possessed by the system by virtue of the increased motion of the particles by virtue of a transfer  of heat, when the content of the system is heated

The thermal energy, Q is given by the following equation;

Q = Mass, m × The specific heat capacity, C × The change in temperature, ΔT

Given that the graduated cylinder with more water has more mass and therefore, more water molecules, than the cylinder with less water, the cylinder with more water has more thermal energy.

3 0
3 years ago
A satellite is launched to orbit the Earth at an altitude of 2.90 x10^7 m for use in the Global Positioning System (GPS). Take t
marin [14]

Answer:

T=66262.4s

Explanation:

From the question we are told that:

Altitude A=2.90 *10^7

Mass m=5.97 * 10^{24} kg

Radius r=6.38 *10^6 m.

Generally the equation for Satellite Speed is mathematically given by

V=(\frac{GM}{d} )^{0.5}

V=(\frac{6.67*10^{-11}*5.97 * 10^{24}}{6.38 *10^6+2.90 *10^7} )^{0.5}

V=3354.83m/s

Therefore

Period T is Given as

T=\frac{2 \pi *a}{V}

T=\frac{2 \pi *(6.38 *10^6+2.90 *10^7}{3354.83}

T=66262.4s

4 0
3 years ago
Fill in the blank
elixir [45]
Is there any types of answer to get an idea
8 0
3 years ago
Read 2 more answers
A box slides to the right along a horizontal surface which is true about the friction force
mixer [17]

Answer:

It is a force in the direction of the motion that allows the box to move

Explanation:

7 0
3 years ago
Earth’s polar ice caps contain about 2.3 × 1019 kg of ice. This mass contributes essentially nothing to the moment of inertia of
sp2606 [1]

Answer:

Explanation:

Initial moment of inertia of the earth I₁ = 2/5 MR² , M is mss of the earth and R is the radius . If ice melts , it forms an equivalent shell of mass  2.3 x 10¹⁹ Kg

Final moment of inertia I₂ = 2/5 M R² + 2/3  x 2.3 x 10¹⁹ x R²

For change in period of rotation we shall apply conservation of angular momentum law

I₁ ω₁  = I₂ ω₂  ,  ω₁ and   ω₂ are angular velocities initially and finally .

I₁ / I₂     =  ω₂ / ω₁

I₁ / I₂     =  T₁ / T₂  , T₁ , T₂ are time period initially and finally .

T₂ / T₁ = I₂ / I₁

(2/5 M R² + 2/3  x 2.3 x 10¹⁹ x R²) / 2/5 MR²

1 + 5 / 3  x 2.3 x 10¹⁹ / M

= 1 + 5 / 3  x 2.3 x 10¹⁹ / 5.97 x 10²⁴

= 1 + .0000064

T₂ = 24 (1 + .0000064)

= 24 hours + .55 s

change in length of the day = .55 s .

3 0
3 years ago
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