All the boats operating at night requires Navigation light.
Navigation light helps prevent collisions between boats and see if visibility is poor. The types of boat are : Rowboats, Tug boats, Vessels, Sailboat etc.
Various boats have different lightning color to show its use and side of the boat.
Answer:
a) P = 1240 lb/ft^2
b) P = 1040 lb/ft^2
c) P = 1270 lb/ft^2
Explanation:
Given:
- P_a = 2216.2 lb/ft^2
- β = 0.00357 R/ft
- g = 32.174 ft/s^2
- T_a = 518.7 R
- R = 1716 ft-lb / slug-R
- γ = 0.07647 lb/ft^3
- h = 14,110 ft
Find:
(a) Determine the pressure at this elevation using the standard atmosphere equation.
(b) Determine the pressure assuming the air has a constant specific weight of 0.07647 lb/ft3.
(c) Determine the pressure if the air is assumed to have a constant temperature of 59 oF.
Solution:
- The standard atmospheric equation is expressed as:
P = P_a* ( 1 - βh/T_a)^(g / R*β)
(g / R*β) = 32.174 / 1716*0.0035 = 5.252
P = 2116.2*(1 - 0.0035*14,110/518.7)^5.252
P = 1240 lb/ft^2
- The air density method which is expressed as:
P = P_a - γ*h
P = 2116.2 - 0.07647*14,110
P = 1040 lb/ft^2
- Using constant temperature ideal gas approximation:
P = P_a* e^ ( -g*h / R*T_a )
P = 2116.2* e^ ( -32.174*14110 / 1716*518.7 )
P = 1270 lb/ft^2
Answer:
C. Recheck the numbers of each atom on each side of the equation
to make sure the sides are equal.
D. Choose coefficients that will balance the equation
Explanation:
In balancing of chemical equation, the number of atoms on both sides must be equal in adherence to the law of conservation of mass.
Using the method of inspection, the equation is first observed to know the relationship between the combining atoms and the resulting ones.
After observing the reaction, put a coefficient that will balance the equation. Then recheck the number of each atom on both side of the equation. One can repeat the process till the equation is balanced.
Answer:
well for one it can be from drilling or when water starts to breck down the rocks
Explanation:
Answer:
The magnetic field is
Explanation:
From the question we are told that
The mass of the metal rod is
The current on the rod is
The distance of separation(equivalent to length of the rod ) is
The coefficient of kinetic friction is
The kinetic frictional force is
The constant speed is
Generally the magnetic force on the rod is mathematically represented as
For the rod to move with a constant velocity the magnetic force must be equal to the kinetic frictional force so
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