3 years ago

Two consecutive positive integers have a

Mathematics

1 answer:

Vlad [161]3 years ago

4 0

Answer:

3, 4

Step-by-step explanation:

x(x+1)=12

x^2+x-12=0

a=1, b=1, c=-12 in the quadratic formula

quadratic formula: ax^2+bx+c = 0

quadratic equation: x=(-b +/- √(b^2-4ac)) / 2a

= (-1 +/- √49 ) / 2

(-1 +/- 7) / 2

x= -4, x=3

-4 doesn't work because it is not positive

Therefore: Answer = 3, 4

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