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Ahat [919]
3 years ago
9

What did Edwin Hubble discover about galaxies that allowed him to determine the expansion rate of the universe?

Physics
1 answer:
mario62 [17]3 years ago
6 0
<span> The farther away a galaxy is, the more its light
is shifted toward the red end of the spectrum. (C)</span>
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Which of the following statements describes the trend in the data?
AURORKA [14]

Answer:

Explanation:

The answer is D- The number of flies decreased, then leveled off.

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2 years ago
What does an electromagnet have that a bar magnet does not ?
Anon25 [30]
The bar magnet and the electromagnet act identical. The difference being a electromagnet is a coil of wire that has a power source connect to both ends, this energizes the coil with an electromagnetic field.
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3 years ago
Scientist use conversion factors to express the given value of a unit different type of unit true or false
kykrilka [37]
True.

<span>Scientist use conversion factors to express the given value of a unit different type of unit</span>

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3 years ago
Read 2 more answers
A square loop of wire lies in the x, y plane with opposite corners at (0, 0) and (a, a). The loop carries a current I directed t
Ket [755]

Answer:

Please refer to the figure.

Explanation:

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5 0
3 years ago
How high would you have to lift a 1000kg car to give it a potential energy of:
Elza [17]

Given parameters:

Mass of the car = 1000kg

Unknown:

Height  = ?

To find the heights for the different amount potential energy given, we need to understand what potential energy is.

Potential energy is the energy at rest due to the position of a body.

 It is mathematically expressed as:

          P.E  = mgh

m is the mass

g is the acceleration due to gravity = 9.8m/s²

h is the height of the car

Now the unknown is h, height and we make it the subject of the expression to make for easy calculation.

               h = \frac{P.E }{mg}

<u>For 2.0 x 10³ J;</u>

                  h  = \frac{2000}{1000 x 9.8}   = 0.204m

<u>For 2.0 x 10⁵ J;</u>

                  h  = \frac{200000}{9.8 x 1000}   = 20.4m

<u>For 1.0kJ  = 1 x 10³J; </u>

                  h  = \frac{1000}{9.8 x 1000}   = 0.102m

   

5 0
3 years ago
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