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2 years ago

Calculate the speed of a satellite moving in a stable circular orbit about the Earth at a height of 4930 km .

Physics

1 answer:

svet-max [94.6K]2 years ago

5 0

The speed of the satellite moving in a stable circular orbit about the Earth is 5,916.36 m/s.

<h3>Speed of the satellite</h3>

v = √GM/r

where;

M is mass of Earth
G is universal gravitation constant
r is distance from center of Earth = Radius of earth + 4930 km

v = √[(6.626 x 10⁻¹¹ x 5.97 x 10²⁴) / ((6371 + 4930) x 10³)]

v = 5,916.36 m/s

Thus, the speed of the satellite moving in a stable circular orbit about the Earth is 5,916.36 m/s.

Learn more about speed here: brainly.com/question/6504879

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3 years ago

A current of 17.0 mA is maintained in a single circular loop of 2.00 \mathrm{~m} circumference. A magnetic field of 0.800T is di

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The magnetic moment is -

M = 5.5 x $10^{-3}$ A $m^{2}$ .

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We have to determine the Magnetic moment of the loop.

<h3>What is the formula to calculate the magnetic moment of loop?</h3>

The formula to calculate the magnetic moment of the loop is -

M = NIA

where -

N - Number of turns

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A - Area of the loop

According to the question, we have -

I = 17mA = 0.017A

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C = 2

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Using the formula -

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M = 3.14 x 1 x 0.017 x 0.32 x 0.32

M = 3.14 x 4 x 0.017

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1 year ago

light of wavelength 587.5 nm illuminates a slit of width 0.75 mm. at what distance from the slit should a screen be placed if th

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Explanation:

Using

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Sinစ= (587.5*10^-9) x 0.75*10^-3

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3 years ago