Answer:
33.33j+6.67i km/hr
Explanation:
From the law of conservation of momentum,
Applying,
mu+m'u' = V(m+m')............... Equation 1
Where m = mass of the truck, m' = mass of the car, u = initial velocity of the truck, u' = initial velocity of the car, V = Final velocity.
Note: let j represent the north, and i represent the east
From the question,
Given: m = 1500 kg, u = 60j, m' = 1200 kg, u' = 15i
Substitute these values into equation 1
1500*60j+1200*15i = V(1500+1200)
90000j+18000i = 2700V
V = (90000j+18000i)/2700
V = 33.33j+6.67i km/hr
Answer:
u= 187.61 ft/s
Explanation:
Given that
g= - 32 ft/s²
The maximum height ,h= 550 ft
Lets take the initial velocity = u ft/s
We know that
v²=u² + 2 g s
v=final speed ,u=initial speed ,s=height
When the object reach at the maximum height then the final speed of the object will become zero.
That is why
u²= 2 x 32 x 550
u²= 35200
u= 187.61 ft/s
That is why the initial speed will be 187.61 ft/s
It is an example of personification because personification is when human traits are give to non human things. Sky's cannot cry.
Answer:
3 mA.
Explanation:
The following data were obtained from the question:
Resistor (R) = 500 Ω
Potential difference (V) = 1.5 V
Current (I) =.?
Using the ohm's law equation, we can obtain the current as follow:
V = IR
1.5 = I x 500
Divide both side by 500
I = 1.5 / 500
I = 3×10¯³ A.
Therefore, the current in the circuit is 3×10¯³ A.
Finally, we shall convert 3×10¯³ A to milliampere (mA).
This can be obtained as follow:
Recall:
1 A = 1000 mA
Therefore,
3×10¯³ A = 3×10¯³ × 1000 = 3 mA
Therefore, 3×10¯³ A is equivalent to 3 mA.
Thus, the current in mA flowing through the circuit is 3 mA.
Average speed = (total distance) / (time to cover the distance)
We know:
Average speed = 65 km/hr
Total distance = 1,000 km
Time to cover it = (Driving Time) + 4 hours.
so we can write:
65 km/hr = (1,000 km) / (Driving Time + 4hr)
(I'm going to start calling the driving time 'DT'.
Notice that DT is a number with the units of 'hours'.)
Multiply each side by (DT + 4hr)
(65 km/hr) (DT + 4hr) = 1,000 km
Eliminate parentheses on the left side:
(65·DT km + 260 km) = 1,000 km
Subtract 260km from each side:
65·DT km = 740 km
Divide each side by 65 :
DT = 11.38 hours .
DT (Driving Time) is the time you spent actually driving.
You had to cover the complete 1,000 km in that time.
So while you were driving, you had to do it at a speed of
1,000 km / 11.38 hrs = 87.8 km/hr .
__________________________________________
As long as we're already totally bored by this question,
let's work on it some more, and check my answer:
... Driving for 11.38 hours at a speed of 87.8 km/hr, you cover
(11.38 hr) x (87.8 km/hr) = 999.164 km (close enough to 1,000) .
So far, so good. The distance is taken care of.
With the 4-hour stop, the total trip takes 4 more hours = 15.38 hours.
So the average speed is
(1,000 km) / (15.38 hr) = 65.02 km/hr
Close enough to 65 km/hr. yay !
