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balandron [24]
3 years ago
13

The largest cross-section of the sphere shown has an approximate area of 28.27 cm2, what is the approximate volume of the sphere

? A) 14.14 cm3 B) 113.1 cm3 C) 226.2 cm3 D) 904.78 cm3
Mathematics
2 answers:
mrs_skeptik [129]3 years ago
5 0

Answer:

B) 113.1 cm³

Step-by-step explanation:

The cross-section of a sphere is a circle.  The area of a circle is:

A = πr²

The largest cross section passes through the center of the sphere, where the radius of the circle equals the radius of the sphere.

28.27 = πr²

r = 3.00

The volume of the sphere is therefore:

V = 4/3 π r³

V = 4/3 π (3.00)³

V = 113.1

nalin [4]3 years ago
3 0

Answer:

B

Step-by-step explanation:

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Which of the following points lies on the circle whose center is at the origin and whose radius is 10?
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Simplify the expression: 2(4 + 6j)
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\boxed{ \bold{ \huge{ \boxed{ \sf{8 + 12j}}}}}

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\sf{2(4 + 6j)}

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8 0
4 years ago
Find the formula for the area A and the perimeter P of the shape shown find the area and perimeter when R is 5 cm find R when A
Ghella [55]

Answer:

1)Area; A = ¼πr²

Perimeter; P = πr/2 + 2r

2)A = 19.63 cm²

P = 17.85 cm

3) r = 8.885 cm

4) r = 14 cm

Step-by-step explanation:

This is a quadrant of a circle. Thus;

Area of a circle is πr². A quadrant is a quarter of a circle. Thus;

Formula for Quadrant Area is; A = ¼πr²

A) Perimeter of a circle is 2πr. Thus, perimeter of a quadrant is a quarter of the full circle perimeter.

Formula for the quadrant perimeter in the image given is;

P = 2πr/4 + 2r

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P = π(5)/2 + 2(5)

P = 17.85 cm

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¼πr² = 100

r² = 100 × 4/π

r² = 78.9358

r = √78.9358

r = 8.885 cm

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50 = πr/2 + 2r

50 = (½π + 2)r

r = 50/(½π + 2)

r = 14 cm

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