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4 years ago

7

PLEASE HELP FAST. EASY POINTS

1 answer:

MrRa [10]4 years ago

6 0

To find the box to the top left, we can multiple the sides like rectangles. To find the top left box, we can multiply -1 and 0.5y to get -0.5y.

To find the box on the bottom right, we can multiply the sides like rectangles again. To find the bottom right box, we can multiply 24x and 3 to get 72x.

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URGENT !!!!!!!!! Please answer correctly !!!!! Will be marking Brianliest !!!!!!!!!!!!!!!!

Morgarella [4.7K]

-2/5
Step by Step :
18 - 8 = 10
-15 - 10 = -25
10/-25 = -2/5

8 0

3 years ago

Which statement compares the limit as x approaches –4 for the two graphs? In both graph I and graph II, the limit is 5. In both

IceJOKER [234]

Selling . Recut read. Your graph 3

4 0

3 years ago

Read 2 more answers

Determine the mean of the numbers 6, 17, 22, 28, and 37.

Kipish [7]

To find the mean or the avg you add up all the numbers you have and then divide by how many numbers you added together in this case 5

$6+ 17+22+28+37=110$

$\frac{110}{5} =22$

so the mean is 22, hope this helped you!

4 0

3 years ago

I can’t figure out how to use the zeros in the polynomial. Please explain

Temka [501]

Answer:

a) $P (x) = (x + 3) (x-1) (x-4)$

b) $P (x) = (2x + 5) (5x - 4) (x-6)$

c) $P (x) = (x-3) (x-1) (x-4) (x + 1) ^ 2$

Step-by-step explanation:

<u>For the question a *</u> you need to find a polynomial of degree 3 with zeros in -3, 1 and 4.

This means that the polynomial P(x) must be zero when x = -3, x = 1 and x = 4.

Then write the polynomial in factored form.

$P (x) = (x + 3) (x-1) (x-4)$

Note that this polynomial has degree 3 and is zero at x = -3, x = 1 and x = 4.

<u>For question b, do the same procedure</u>.

Degree: 3

Zeros: -5/2, 4/5, 6.

The factors are

$x = -\frac{5}{2}\\\\x +\frac{5}{2} = 0\\\\(2x +5) = 0$

---------------------------------------

$x =\frac{4}{5}\\\\x-\frac{4}{5} = 0\\\\(5x-4) = 0$

--------------------------------------

$x = 6\\\\(x-6) = 0$

--------------------------------------

$P (x) = (2x + 5) (5x - 4) (x-6)$

<u>Finally for the question c we have</u>

Degree: 5

Zeros: -3, 1, 4, -1

Multiplicity 2 in -1

$x = -3\\\\(x-3) = 0$

--------------------------------------

$x = 1\\\\(x-1) = 0$

--------------------------------------

$x = 4\\\\(x-4) = 0$

----------------------------------------

$x = -1\\\\(x + 1) = 0$

-----------------------------------------

$P (x) = (x-3) (x-1) (x-4) (x + 1) ^ 2$

8 0

3 years ago

HELP PLEASE!!! I don’t understand these math questions at all and it’s due in 2 hours, I’m freaking out

nataly862011 [7]

Answer:

1. The top and bottom lines (-5,3) (8,3) is parallel to line (-2,-2) (11,-2). The sides Lines (-5,3) (-2,-2) is parallel to line (8,3) (11,-2).

2. None of the line create a right angle. None are able to create a box at the angle

4 0

3 years ago