To show that they used the same amount of ribbon you could take the 1 yard and divided into different sized equal groups.
1 yard divided by four equals 1/4 yard for each of four ribbons.
1 yard divided by six equals 1/6 yard for each of six ribbons.
You could have ribbons the size of 1/4 our yard and 1/6 yard, but you would have different amounts of each.
First, let's convert all of these numbers to decimal form:
(This will make it much easier to compare.)
- 0.6, - 0.625, - 0.4117, - 0.72
Now we can list them from least to greatest!
-0.4117, - 0.6, -0.625, -0.72
And don't forget to convert the selective decimals that we converted earlier back into fractions!
Therefore, the final list would be:
- 7/17, - 0.6, - 5/8, - 0.72
Hope this helps!
See https://web2.0calc.com/questions/help_29603.
Answer:
57.93% probability that a trip will take at least 35 minutes.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a trip will take at least 35 minutes
This probability is 1 subtracted by the pvalue of Z when X = 35. So



has a pvalue of 0.4207
1 - 0.4207 = 0.5793
57.93% probability that a trip will take at least 35 minutes.