1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Pepsi [2]
4 years ago
5

The number of emails a friend received each day over the last 20 days is shown below create a cumulative frequency table that re

presents the data. for how many days did she receive 19 or fewer emails?
15 22 18 9 32 35 14 10 34 45 21 25 6 12 7 14 16 20 5 37
Mathematics
1 answer:
marishachu [46]4 years ago
8 0
Counting the number tabulated in the given above, it can be concluded that indeed there were 20 days in consideration. To determine how many days did they receive 19 or fewer emails, we just have to count the number less than 20. That is, 13 days out of the 20 working days. 
You might be interested in
PLEASE HELP ME GEOMETRY
worty [1.4K]
So the X coordinate is 4, and the Y is -5. The rule says X + 2, Y - 8 so (4) + 2, (-5) - 8.

It's D (6, -13)

5 0
3 years ago
Read 2 more answers
PLEASE HELP 15 POINTS N BRAINLIEST
Mrac [35]

Answer:

OK don't worry we will help you get 15 points

5 0
3 years ago
Read 2 more answers
For question 10e I wrote my answer as t=19, is that correct?
garri49 [273]

Answer:

1/19

Step-by-step explanation:

3(7) -2 = 19, this would be g(7) but they want g^-1 (7) so you need the inverse of your answer:
1/19.

HOPE THIS HELPS & MAKES SENSE!!!

3 0
3 years ago
On Martin's first stroke, his golf ball traveled 4/5 of the distance to the hole. On his second stroke, the ball traveled 79 met
Sav [38]

Answer:

0.395 kilometre

Step-by-step explanation:

Given:

On Martin's first stroke, his golf ball traveled 4/5 of the distance to the hole.

On his second stroke, the ball traveled 79 meters and went into the hole.

<u>Question asked:</u>

How many kilometres from the hole was Martin when he started?

<u>Solution:</u>

Let distance from Martin starting point to the hole in meters = x

On Martin's first stroke, ball traveled = \frac{4}{5} \ of \ total \ distance\ to\ the\ hole

                                                             =\frac{4}{5} \times x=\frac{4x}{5}

On his second stroke, the ball traveled and went to the hole = 79 meters

Total distance from starting point to the hole = Ball traveled from first stroke + Ball traveled from second stroke

x=\frac{4x}{5} +79\\ \\ Subtracting\ both\ sides\ by \ \frac{4x}{5}\\ \\ x- \frac{4x}{5}= \frac{4x}{5}- \frac{4x}{5}+79\\ \\ \frac{5x-4x}{5} =79\\ \\ By \ cross\ multiplication\\ \\ x=79\times5\\ \\ x=395\ meters

Now, convert it into kilometre:

1000 meter = 1 km

1 meter = \frac{1}{1000}

395 meters = \frac{1}{1000}\times395=0.395\ kilometre

Thus, there are 0.395 kilometre distance from Martin starting point to the hole.

8 0
3 years ago
Please help me out!!
jok3333 [9.3K]
The answer is

y=3x + 5




good luck
6 0
4 years ago
Other questions:
  • A textbook search committee is considering 13 books for possible adoption. The committee has decided to select 3 of the 13 for f
    8·1 answer
  • Who ever helps me with all theses you will get 50 points​
    14·2 answers
  • Midnight Mocha is a 24-hour café that specializes in coffee drinks. It has a drive- through that is almost fully automated. Eac
    14·1 answer
  • Please help!! I’ve tried to answer this but I’m off a few cents every time.
    5·1 answer
  • Find the sum of the first 5 terms of the sequence 4,2,0
    13·2 answers
  • .Write the quadrants/axes in which the following points lie a) (2,-3) b)(0,8) c)(-1,-2) d)(4,7)
    13·1 answer
  • 1/4 divided 3 please help me
    10·1 answer
  • NEED HELP ASAP! WILL GIVE BRAINLIEST!
    11·1 answer
  • Pls help me im so confused and i need this done!
    5·2 answers
  • David has a stack of 30 cards, which are numbered 1 through 30. what is the exact probability of randomly selecting a card from
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!