Answer:
Explanation:
Lisoprisil's molecular mass is 405.488g/mol, we'll use this fact to calculate molarity, which units are mol/L, and we proceed to the calculus:
- First, we'll unify unities, the 10 milligrams of lisinopril we'll transform into grams.
- Now that we have the same unities we'll calculate molarity using the molecular mass, the grams of lisinopril and the liters in which these grams are, let's consider that our final unities have to be mol/L.
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The volume of Sulfur dioxide-SO₂ at STP : = 102.144 L
<h3>Further explanation</h3>
Given
4.56 mol Sulfur dioxide-SO₂
Required
The volume
Solution
Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters/mol.
so for 4.56 mol :
= 4.56 x 22.4 L
= 102.144 L
Answer:
527.184 J of heat is removed from a 21 g water sample if it is cooled from 34.0 ° C to 28.0 ° C.
Explanation:
Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
When the heat added or removed from a substance causes a change in temperature in it, this heat is called sensible heat.
In other words, the sensible heat of a body is the amount of heat received or transferred by a body when it undergoes a change in temperature without there being a change in physical state (solid, liquid or gaseous). The equation that allows to calculate this heat exchange is:
Q = c * m * ΔT
Where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c and where ΔT=Tfinal-Tinitial is the change in temperature.
In this case:
- c= 4.184
- m=21 g
- ΔT=Tfinal-Tinitial=28 °C - 34 °C=-6 °C
Replacing:
Q= 4.184 * 21 g* (-6 C)
Q= - 527.184 J
To lower the temperature, heat has to be given, for that the final temperature must be lower than the initial temperature; and it receives the name of transferred heat and has a negative value, as in this case.
<u><em>
527.184 J of heat is removed from a 21 g water sample if it is cooled from 34.0 ° C to 28.0 ° C.</em></u>
Answer:
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Explanation:
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