Molarity is simply the ratio of the number of moles of a
substance over the total volume of the solution. Assuming that the addition of
0.850 moles does not change the overall volume of 1.70 L, therefore molarity is
simply:
Molarity = 0.850 moles / 1.70 L = 0.5 moles / L = 0.5 M
Answer:
1) Monochrome
2) Monocot
3) Monosaccharide
4) Monounsaturated
5) Monoxide
Explanation:
The prefix mono or mon is of Greek origin and it means single, lone or one.
From the meaning of the words we can tell that they have something in common:
1) Monochrome: This refers to an artwork, a painting or drawing that has just one color.
2) Monocot: This is a type of flowering plant that has a single embryo and a single cotyledon.
3) Monosaccharide: This is a type of simple sugar that contains one sugar unit that cannot be split.
4) Monounsaturated: This refers to a molecule that contains one double or triple bond.
5) Monoxide: This refers to a form of oxide that contains only one oxygen atom.
From the definitions above, all the words mean having only one or a single item.
That is what they have in common.
Answer:
0.20 mol's
Explanation:
1.675 L = 1.675 dm^3
moles = V/(conc):
moles = 1.675/(8.5)
moles = 0.1970... --> 0.20
Answer:
114 kPa
Explanation:
By Bernoulli's equation when a fluid flows steadily through a pipe:
P + ρ*g*y + v² = constant in the pipe, where P is the pressure, ρ is the density of the fluid, g is the gravity acceleration (9.8 m/s²), y is the high, and v the velocity.
By the continuity equation, the liquid flow must be constant in the pipe, and then:
A1*v1 = A2*v2
Where A is the area, v is the velocity, 1 is the point 1, and 2 the point 2 in the pipe. The are is the circle area: π*(d/2)². So:
π*(0.105/2)²*9.91 = π*(0.167/2)²*v2
0.007v2 = 0.027
v2 = 3.9 m/s
Then:
P1 + ρ*g*y1 + v1² = P2 + ρ*g*y2 + v2²
ρ*g*y1 - ρ*g*y2 + v1² - v2² = P2 - P1
ρ*g*Δy + v1² - v2² = ΔP
ΔP = 1290*9.8*9.01 + 9.91² - 3.9²
ΔP = 113,987.42 Pa
ΔP = 114 kPa
A neutral atom becomes a negatively charged ion by accepting electrons.
For example:
F + e⁻ → F⁻
S + 2e⁻ →S²⁻
