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leva [86]
3 years ago
7

When you combine chocolate powder and milk, the result is best describe as?

Chemistry
2 answers:
Butoxors [25]3 years ago
4 0

Answer:

suspension solution

Explanation:

Suspension solution -

The mixture of two or more substance , to obtain a solution , where the constituents can be observed with naked eye .

Hence , milk and chocolate powder leads a homogeneous solution , but after keeping it for some time , the chocolate particles will settle down , making a suspension solution .

Hence , the answer is suspension solution .

NeX [460]3 years ago
3 0
Answer:

The answer to your question would be substance, but chocolate power mixed into milk would be more of a suspension.

Explanation:

Neither chocolate powder nor milk are elements. They are both complex molecules. Their mixture will not result in the formation of a compound since no chemical reaction will take place.

The molecules of the chocolate powder will simply intermingle with the fatty molecules of the milk to form the substance.

When thoroughly mixed the solution will become homogeneous so there will be no lumps of chocolate power visible. But after time, the chocolate will become visible at the bottom of the clear container in which we asked you to prepare the mixture.

HOPE THIS HELPS :)

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<em>Given the noble gas configuration of an element: [Ar] 4s2, 3d5, what is the element? </em>

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Hope this helps!

6 0
3 years ago
A student investigates the properties of an unknown liquid substance in a beaker. The student finds the substance has a mass of
shtirl [24]

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The substance is a mixture because it left a white powder in the beaker when boiled.

Explanation:

8 0
3 years ago
A substance is analyzed and found to contain 85.7% carbon and 14.3% hydrogen by weight. A gaseous sample of the substance is fou
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Answer:

The empirical formula of the compound is CH2

Explanation:

<u>Step 1:</u> Data given

A substance contains 85.7 % carbon and 14.3 % hydrogen.

The substance has a density of 1.87 g/L

1 mol occupies 22.4 L

Molar mass of carbon = 12 g/mol

Molar mass of hydrogen = 1.01 g/mol

<u>Step 2</u>: Calculate molar mass of the substance

Since 1 mol occupies 22.4 L;

1 mol of this substance = 1.87g/L *22.4 = 41.888 grams

This means the molar mass of the substance is 41.888 g/mol

<u>Step 3:</u> Calculate mass of carbon:

85.8 % is carbon

this means 41.888 * 0.858 = 35.94 grams

<u>Step 4: </u>Calculate moles of carbon

moles C = mass C/ Molar mass C

Moles C = 35.94 grams / 12 g/mol

Moles C = 2.995 moles

<u>Step 5:</u> Calculate mass of hydrogen:

14.3 % is hydrogen

this means 41.888 * 0.143 = 5.99 grams

<u>Step 6 :</u>Calculate moles of hydrogen

Moles H  = 5.99 grams / 1.01 g/mol

Moles H = 5.93 moles

<u>Step 7: </u>Calculate  mol ratio

Ratio C:H = 1:2

The empirical formule = CH2

<u>Step 8</u>: calculate molar formule

Molar mass of empirical formule = 14.02 g/mol

n = Molar mass of substance / molar mass of empirical formule

n = 41.888 / 14.02 = 3

This means we have to multiply the empirical formula by 3

3*(CH2) = C3H6

C3H6 can be propene or cyclopropane

5 0
3 years ago
n a coffee cup calorimeter, 100.0 mL of 1.0M NaOH and 100.0 mL of 1.0M HCl are mixed. Both solutions were originally at 24.6 deg
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Answer:

Explanation:

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This is the enthalpy change required.

3 0
4 years ago
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