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3 years ago

Write a balanced equation for the following neutralization reaction HBr+LiOH<->

Chemistry

1 answer:

Sophie [7]3 years ago

8 0

Answer:

HBr(aq) + LiOH(aq) = LiBr(aq) + H2O(l)

Explanation:

For this reaction, the reactants are the hydrobomic acid and the lithium hydroxide which produces the products lithium bromide and water.

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The _______ of an atom are negatively charged. a. protons b. negatrons c. neutrons d. electrons

PIT_PIT [208]

Protons = +1
negatrons = -1
neutrons = 0
<span>electrons = -1
</span>
<span>negatrons are like positrons and they are subatomic particles and are not present in atoms
</span>
so electrons are negatively charged and are present in atoms

hope that helps

7 0

3 years ago

Read 2 more answers

Which of the following is not a source of air pollution related to human activities

tangare [24]

Radon is <span>not a source of air pollution related to human activities</span>

8 0

4 years ago

Read 2 more answers

Calculate ΔGrxn for this equation, rounding your answer to the nearest whole number. CaCO3(s) → CaO(s) + CO2(g) ΔGf,CaCO3 = −1,1

FrozenT [24]

Answer: $\Delta G_{rxn}$ for the given reaction is 130.19kJ/mol

Explanation:

To Calculate the $\Delta G_{rxn}$ , we use the formula:

$\Delta G_{rxn}=\Delta G_{products}-\Delta G_{reactants}$

For the given chemical reaction:

$CaCO_3(s)\rightarrow CaO(s)+CO_2(g)$

We are given:

$\Delta G_{CaCO_3}=-1128.76kJ/mol\\\Delta G_{CaO}=-604.17kJ/mol\\\Delta G_{CO_2}=-394.4kJ/mol$

Now, to calculate $\Delta G_{rxn}$ , we put the values in the above equation:

$\Delta G_{rxn}=(\Delta G_{CaO}+\Delta G_{CO_2})-\Delta G_{CaCO_3}$

$\Delta G_{reaction}=(-604.17-394.4)-(-1128.76)kJ/mol\\\Delta G_{reaction}=130.19kJ/mol$

As, the value of $\Delta G_{reaction}$ comes out to be positive, the reaction is said to be non-spontaneous reaction.

3 0

3 years ago

According to Graham’s law, the rate of effusion of a gas is inversely proportional to

VLD [36.1K]

C. the square root of the mass of the particles.

<h3>Further explanation </h3>

Graham's law: the rate of effusion of a gas is inversely proportional to the square root of its molar masses or

the effusion rates of two gases = the square root of the inverse of their molar masses:

$\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }$

$\rm M_1\times r_1^2=M_2\times r_2^2$

From this equation shows that the greater the mass of the gas, the smaller the effusion rate of the gas and vice versa, the smaller the mass of the gas, the greater the effusion velocity.

So if both gases are at the same temperature and pressure, the above formula can apply

5 0

3 years ago

Choose any metal atom from Group 1A, 2A, or 3A. What charge will it adopt when it ionizes?

Ksenya-84 [330]

Answer:

Positive charge.

Explanation:

Hello!

In this case, since elements belonging to groups 1A, 2A and 3A are mostly metals, we infer they have the capacity to lose electrons and therefore they become positively charged.

Some examples may be:

$Na^+\\\\H^+\\\\Ca^{2+}\\\\Al^{3+}\\\\Sr^{2+}$

Best regards!

6 0

3 years ago