All categories

3 years ago

Helllppppppppp....don't guess !!!

Chemistry

2 answers:

noname [10]3 years ago

7 0

Answer:

it answer D because waste is flowing thru the air

Zielflug [23.3K]3 years ago

7 0

D because when you burn something it releases gases into the air

You might be interested in

Be sure to answer all parts. The percent by mass of bicarbonate (HCO3−) in a certain Alka-Seltzer product is 32.5 percent. Calcu

pochemuha

Answer : The volume of $CO_2$ will be, 514.11 ml

Explanation :

The balanced chemical reaction will be,

$HCO_3^-+HCl\rightarrow Cl^-+H_2O+CO_2$

First we have to calculate the mass of $HCO_3^-$ in tablet.

$\text{Mass of }HCO_3^-\text{ in tablet}=32.5\% \times 3.79g=\frac{32.5}{100}\times 3.79g=1.23175g$

Now we have to calculate the moles of $HCO_3^-$ .

Molar mass of $HCO_3^-$ = 1 + 12 + 3(16) = 61 g/mole

$\text{Moles of }HCO_3^-=\frac{\text{Mass of }HCO_3^-}{\text{Molar mass of }HCO_3^-}=\frac{1.23175g}{61g/mole}=0.0202moles$

Now we have to calculate the moles of $CO_2$ .

From the balanced chemical reaction, we conclude that

As, 1 mole of $HCO_3^-$ react to give 1 mole of $CO_2$

So, 0.0202 mole of $HCO_3^-$ react to give 0.0202 mole of $CO_2$

The moles of $CO_2$ = 0.0202 mole

Now we have to calculate the volume of $CO_2$ by using ideal gas equation.

$PV=nRT$

where,

P = pressure of gas = 1.00 atm

V = volume of gas = ?

T = temperature of gas = $37^oC=273+37=310K$

n = number of moles of gas = 0.0202 mole

R = gas constant = 0.0821 L.atm/mole.K

Now put all the given values in the ideal gas equation, we get :

$(1.00atm)\times V=0.0202 mole\times (0.0821L.atm/mole.K)\times (310K)$

$V=0.51411L=514.11ml$

Therefore, the volume of $CO_2$ will be, 514.11 ml

6 0

3 years ago

How many molecules are present in 2 H₂ SO4

fomenos

Answer:

in H2So4 splits in 2 H+ and a

so42 -particle=3particle per mole.So2

moles H2So4 will result in 3*2=6moles

of molecules.

5 0

3 years ago

Read 2 more answers

The factor that is changed throughout an experiment is called the _______. A. apparatus B. constant C. variable D. hypothesis

ser-zykov [4K]

The variable is what changes during an experiment. Hopefully this helped! :)

4 0

3 years ago

Read 2 more answers

Which amount of a compound dissolved in 100g of water at the stated temperature represents a solution that is saturated

Assoli18 [71]

40 g KNO, at 25°C

Brainlist?

5 0

3 years ago

How much heat must your body transfer to 500.0g of water to heat it from 25.0°C to body temperature, 37.0°C?

shtirl [24]

Answer : The heat your body transfer must be, 25.1 kJ

Explanation :

Formula used :

$Q=m\times c\times \Delta T$

or,

$Q=m\times c\times (T_2-T_1)$

where,

Q = heat = ?

m = mass of water = 500.0 g

c = specific heat of water = $4.18J/g^oC$

$T_1$ = initial temperature = $25.0^oC$

$T_2$ = final temperature = $37.0^oC$

Now put all the given value in the above formula, we get:

$Q=500.0g\times 4.18J/g^oC\times (37.0-25.0)K$

$Q=25080J=25.1kJ$

Therefore, the heat your body transfer must be, 25.1 kJ

3 0

3 years ago

Helllppppppppp....don't guess !!!​

Helllppppppppp....don't guess !!!