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Amiraneli [1.4K]
3 years ago
8

Nitric acid, , is manufactured by the Ostwald process, in which nitrogen dioxide, , reacts with water. How many grams of nitroge

n dioxide are required in this reaction to produce 6.40 g ? g
Chemistry
1 answer:
aleksandr82 [10.1K]3 years ago
5 0

Answer:

7.04 g

Explanation:

Let's consider the reaction in the last step of the Ostwald process.

3 NO₂(g) + H₂O(l) → 2 HNO₃(aq) + NO(g)

The molar mass of HNO₃ is 63.01 g/mol. The moles corresponding to 6.40 g are:

6.40 g × (1 mol/63.01 g) = 0.102 mol

The molar ratio of NO₂ to HNO₃ is 3:2. The reacting moles of NO₂ are:

0.102 mol HNO₃ × (3 mol NO₂/2 mol HNO₃) = 0.153 mol NO₂

The molar mass of NO₂ is 46.01 g/mol. The mass corresponding to 0.153 moles is:

0.153 mol × (46.01 g/mol) = 7.04 g

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How many grams of nitric acid HNO₃, are required to neutralize (completely react with) 4.30 grams of Ca(OH)2 according to the ac
Brrunno [24]

Answer:

7.32g of HNO3 are required.

Explanation:

1st) From the balanced reaction we know that 2 moles of HNO3 react with 1 mole of Ca(OH)2 to produce 2 moles of H2O and 1 mole of Ca(NO3)2.

From this, we find that the relation between HNO3 and Ca(OH)2 is that 2 moles of HNO3 react with 1 mole of Ca(OH)2.

2nd) This is the order of the relations that we have to use in the equation to calculate the grams of nitric acid:

• starting with the 4.30 grams of Ca(OH)2.

,

• using the molar mass of Ca(OH)2 (74g/mol).

,

• relation of the 2 moles of HNO3 that react with 1 mole of Ca(OH)2 .

,

• using the molar mass of HNO3 (63.02g/mol).

4.30g\text{ Ca\lparen OH\rparen}_2*\frac{1\text{ mol Ca\lparen OH\rparen}_2}{74g\text{ Ca\lparen OH\rparen}_2}*\frac{2\text{ moles HNO}_3}{1\text{ mole Ca\lparen OH\rparen}_2}*\frac{63.02g\text{ HNO}_3}{1\text{ mole HNO}_3}=7.32g\text{ HNO}_3

So, 7.32g of HNO3 are required.

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tensa zangetsu [6.8K]
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PLEASE HELP ME
ki77a [65]

Answer:

1.15 atm

Explanation:

According to Dalton's law of partial pressures, the total pressure is the sum of all the partial pressures of the gases present in the mixture.

Therefore we have:

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We were given the following:

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Therefore:

2.45 = x + 0.65 + 0.65

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x = 2.45 - 1.3

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High temperature and pressure produce the highest rate of reaction. However, this must be balanced with the high cost of the energy needed to maintain these conditions. Catalysts increase the rate of reaction without affecting the yield. This can help create processes which work well even at lower temperatures.

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