There are 26 electrons in the nickel ion in the compound NiS.
<h3>How many electrons does the nickel ion contain in the compound NiS?</h3>
The number of electrons in a neutral Nickel atom is obtained from the atomic number of Nickel.
The atomic number of Nickel is 28, therefore, the neutral nickel atom has 28 electrons.
In the compound NiS, nickel atom loses two electrons to to form the nickel ion.
Number of electrons left = 28 - 2 = 26
Therefore, there are 26 electrons in the nickel ion in the compound NiS.
In conclusion, nickel atom loses two electrons to form nickel ion in NiS.
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Answer:
63 mL
Explanation:
To find the amount of mililiters in an amount of liters, we must multiply by the amount of liters by 1000.
0.063 L × 1000 = 63 mL
its 40
I just took the test right now to get this answer
Answer:
K = Ka/Kb
Explanation:
P(s) + (3/2) Cl₂(g) <-------> PCl₃(g) K = ?
P(s) + (5/2) Cl₂(g) <--------> PCl₅(g) Ka
PCl₃(g) + Cl₂(g) <---------> PCl₅(g) Kb
K = [PCl₃]/ ([P] [Cl₂]⁽³'²⁾)
Ka = [PCl₅]/ ([P] [Cl₂]⁽⁵'²⁾)
Kb = [PCl₅]/ ([PCl₃] [Cl₂])
Since [PCl₅] = [PCl₅]
From the Ka equation,
[PCl₅] = Ka ([P] [Cl₂]⁽⁵'²⁾)
From the Kb equation
[PCl₅] = Kb ([PCl₃] [Cl₂])
Equating them
Ka ([P] [Cl₂]⁽⁵'²⁾) = Kb ([PCl₃] [Cl₂])
(Ka/Kb) = ([PCl₃] [Cl₂]) / ([P] [Cl₂]⁽⁵'²⁾)
(Ka/Kb) = [PCl₃] / ([P] [Cl₂]⁽³'²⁾)
Comparing this with the equation for the overall equilibrium constant
K = Ka/Kb
