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3 years ago

If your vehicle has a steering wheel lock, should you ever turn off the ignition while it is moving?

1 answer:

5 0

It is not advisable to turn off the ignition while it is moving, so it is a no. Why? Even though the vehicle has steering wheel lock, turning off the ignition while it is moving is not advisable because it causes the vehicle to lose out of control, leading to complications and accidents.

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3. Neha travels 4 m towards the north, 3m towards the east, and then 7 m towards south, find the displacement and total distance

Digiron [165]

Answer:

Explanation:

Explanation: total displacement =3√2m. and total distance covered=14m. I hope this is right and helps u.

7 0

3 years ago

xperiments is conducted. In each experiment, two or three forces are applied to an object. The magnitudes of these forces are gi

creativ13 [48]

Answer:

a) b) d)

Explanation:

The question is incomplete. The Complete question might be

In an inertial frame of reference, a series of experiments is conducted. In each experiment, two or three forces are applied to an object. The magnitudes of these forces are given. No other forces are acting on the object. In which cases may the object possibly remain at rest? The forces applied are as follows: Check all that apply.

a)2 N; 2 N

b) 200 N; 200 N

c) 200 N; 201 N

d) 2 N; 2 N; 4 N

e) 2 N; 2 N; 2 N

f) 2 N; 2 N; 3 N

g) 2 N; 2 N; 5 N

h ) 200 N; 200 N; 5 N

For th object to remain at rest, sum of all forces must be equal to zero. Use minus sign to show opposing forces

a) 2+(-2)=0 here minus sign is to show the opposing firection of force

b) 200+(-200)=0

c) 200+(-201) $\neq$ 0

d) 2+2+(-4)=0

e) 2+2+(-2) $\neq$ 0

f) 2+2+(-3) $\neq$ 0; 2+(-2)+3 $\neq$ 0

g) 2+2+(-5) $\neq$ 0; 2+(-2)+5 $\neq$ 0

h)200 + 200 +(-5) $\neq$ 0; 200+(-200)+5 $\neq$ 0

6 0

3 years ago

A particle (mass = 2.0 mg, charge = −6.0 μC) moves in the positive direction along the x axis with a velocity of 3.0 km/s. It en

Virty [35]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The acceleration would be $a = 0.003* 6 =0.018\ m/s^2$

Explanation:

The objective of this solution is to obtain the acceleration of the particle

Now looking at Newton law which is mathematically represented as

$F = ma$

Where F is the force experience by a particle

m is the mass of the particle

a is the acceleration of the particle

And also this force is equivalent to magnetic force in a magnetic field which is mathematically represented as

$F = qvB$

Where q is the charge of the particle

v is the velocity of the charge

B is the magnetic field the charge is under it influence

Now equating this two formulas

$ma = qvB$

Making a the subject we have

$a = \frac{qvB}{m}$

In the question the direction of the is in the positive x-axis which is $i$ hence the direction would be in the $i$ direction

So substituting $(2.0i +3.0j+4.0k)mT = (2.0i +3.0j+4.0k)*10^{-3}T$ for B

$a = \frac{q}{m} * v (2.0i +3.0j +4.0k)*10^{-3}$

Substituting $3.0 Km /s = 3.0*10^{3}\ m/s$ for v and $-6.0 \muC = -6.0*10^{-6} C$ for q

$a = \frac{-6.0*10^{-6}}{2.0*10^{-3}} * 3.0*10^{3} *(2i+3j+4k) *10^{-3}$

$a = 0.003 * 3i(2i+3j+4k)$

$a = 0.003 *((3*2)i \ \cdot i \ +(3*3) i \ \cdot \ j \ + (3*4)i \ \cdot \ k)$

According to vector multiplication

$i \cdot i = j \cdot j = k\cdot k = 1\\\\and \ i\cdot j = i\cdot k = 0$

$a = 0.003* 6 =0.018\ m/s^2$

8 0

3 years ago

Identify the number of and types of elements in this schematic diagram

Nataly_w [17]

-- The long line and short line close together at the left side
   of the diagram represent a single-cell battery.
It's the only one in this diagram.
It's a device that stores chemical energy and delivers it on demand.

-- The zig-zag lines with circles around them represent light bulbs.
There are three of them in this diagram.
They are devices used to produce light by dissipating electrical energy.

-- The zig-zag lines without circles, at the top of the diagram,
   represent resistors.
There are two of them in this diagram.
They are devices used to change or control electrical parameters
   within a circuit by dissipating electrical energy.

-- The short straight line between two small circles at the bottom
   of the diagram represents a switch.
There is only one switch in this circuit.
It's a device used to easily and quickly start or stop the flow of current
    past a certain point in a circuit.

In this circuit ...

-- When the switch is closed (as drawn), the light bulb nearest the battery
glows brightest, the light bulb in the middle glows less bright, and the light
bulb on the right side glows dimmest of all.

-- When the switch is open, the light bulb nearest the battery glows, and
neither of the other two light bulbs glows at all.

4 0

3 years ago

Read 2 more answers

A force of 5 N produces an acceleration of 2 m/s2 on the object. What is the mass of the object?

hichkok12 [17]

Hello!

A force of 5 N produces an acceleration of 2 m/s2 on the object. What is the mass of the object ?

Data:

F (force) = 5 N

m (mass) = ?

a (acceleration) = 2 m/s²

Solving: