By studying meteorites which are the most ancient material in space.
Answer:
So the ratio will be ![\frac{T_L}{T_H}=-0.171](https://tex.z-dn.net/?f=%5Cfrac%7BT_L%7D%7BT_H%7D%3D-0.171)
Explanation:
We have given heat engine absorbs 450 joule from high temperature reservoir
So ![Q=450j](https://tex.z-dn.net/?f=Q%3D450j)
As the heat engine expels 290 j
So work done W = 290 J
We know that efficiency ![\eta =\frac{W}{Q}=\frac{290}{450}=0.6444](https://tex.z-dn.net/?f=%5Ceta%20%3D%5Cfrac%7BW%7D%7BQ%7D%3D%5Cfrac%7B290%7D%7B450%7D%3D0.6444)
It is given that efficiency of the engine only 55 % of Carnot engine
So efficiency of Carnot engine ![=\frac{0.6444}{0.55}=1.171](https://tex.z-dn.net/?f=%3D%5Cfrac%7B0.6444%7D%7B0.55%7D%3D1.171)
Efficiency of Carnot engine is ![\eta =1-\frac{T_L}{T_H}](https://tex.z-dn.net/?f=%5Ceta%20%3D1-%5Cfrac%7BT_L%7D%7BT_H%7D)
![1.171 =1-\frac{T_L}{T_H}](https://tex.z-dn.net/?f=1.171%20%3D1-%5Cfrac%7BT_L%7D%7BT_H%7D)
![\frac{T_L}{T_H}=-0.171](https://tex.z-dn.net/?f=%5Cfrac%7BT_L%7D%7BT_H%7D%3D-0.171)
Answer:
457.81 Hz
Explanation:
From the question, it is stated that it is a question under Doppler effect.
As a result, we use this form
fo = (c + vo) / (c - vs) × fs
fo = observed frequency by observer =?
c = speed of sound = 332 m/s
vo = velocity of observer relative to source = 45 m/s
vs = velocity of source relative to observer = - 46 m/s ( it is taking a negative sign because the velocity of the source is in opposite direction to the observer).
fs = frequency of sound wave by source = 459 Hz
By substituting the the values to the equation, we have
fo = (332 + 45) / (332 - (-46)) × 459
fo = (377/ 332 + 46) × 459
fo = (377/ 378) × 459
fo = 0.9974 × 459
fo = 457.81 Hz
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The answer is C.
An object on the moon is six times lighter than on Earth.