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Nana76 [90]
4 years ago
6

Identify the number of and types of elements in this schematic diagram

Physics
2 answers:
Nataly_w [17]4 years ago
4 0
-- The long line and short line close together at the left side
       of the diagram represent a single-cell battery.
It's the only one in this diagram. 
It's a device that stores chemical energy and delivers it on demand.

-- The zig-zag lines with circles around them represent light bulbs.
There are three of them in this diagram. 
They are devices used to produce light by dissipating electrical energy.

-- The zig-zag lines without circles, at the top of the diagram,
       represent resistors.
There are two of them in this diagram.
They are devices used to change or control electrical parameters
   within a circuit by dissipating electrical energy.

-- The short straight line between two small circles at the bottom
       of the diagram  represents a switch.
There is only one switch in this circuit.
It's a device used to easily and quickly start or stop the flow of current
    past a certain point in a circuit.

In this circuit ...

-- When the switch is closed (as drawn), the light bulb nearest the battery
glows brightest, the light bulb in the middle glows less bright, and the light
bulb on the right side glows dimmest of all.

-- When the switch is open, the light bulb nearest the battery glows, and
neither of the other two light bulbs glows at all.
USPshnik [31]4 years ago
4 0

Answer:

here you go

Explanation:

hope it helps

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Helppppppppppppppppppppppppp
andrew11 [14]

Answer:

value of x=35°

y=72.5°

hope it helps you

make me brainliest plz

6 0
3 years ago
A coil of 150 turns of wire is in the form of a circle of radius 7.5 cm, and sits in the center of a dipole magnet that produces
irga5000 [103]

Answer:

Current in the loop is 0.063 A        

Explanation:

Number of turns in the coil N = 150

Radius of the circular loop r = 7.5 cm = 0.075 m

So area A=\pi r^2=3.14\times 0.075^2=0.0176m^2

Magnetic field B = 1.5 T

Maximum torque is given \tau =0.25Nm

We have to find current in the coil

Torque on circular coil in magnetic field is equal to

\tau =BINA

0.25=1.5\times I\times 150\times 0.0176

I = 0.063 A

7 0
3 years ago
A flying squirrel has a mass of 0. 765 kg. He jumps off the tree and hits the ground with 125 joules of energy. Determine how hi
uranmaximum [27]

Answer:

Height, h = 16.67 m

Explanation:

We have,

Mass of a squirrel is 0.765 kg.

He jumps off the tree and hits the ground with 125 joules of energy.

It is required to find the height up on the tree the squirrel was when it jumped.

The energy possessed by the squirrel is called its gravitational potential energy. It can be given by :

E=mgh

h is height up on the tree the squirrel was when it jumped

h=\dfrac{E}{mg}\\\\h=\dfrac{125\ J}{0.765\ kg\times 9.8\ m/s^2}\\\\h=16.67\ m

So, the squirrel will go to a height of 16.67 m.

6 0
3 years ago
How does gravity keep the moon in orbit around earth
lidiya [134]

Answer:

The moon's orbit draws the oceans to it, which triggers ocean tides. Force produces stars and planets by gathering the mass from which it exists.

Explanation:

The moon's orbit draws the oceans to it, which triggers ocean tides. Force produces stars and planets by gathering the mass from which it exists.

Answer is above

<em><u>Hope this helps.</u></em>

3 0
3 years ago
A soccer player extends her lower leg in a kicking motion by exerting a force with the muscle above the knee in the front of her
lisabon 2012 [21]

Answer:

10.09 N

Explanation:

Analogously to Newton's second law, torque can be defined as:

\tau=I\alpha

Here, I is the moment of inertia and \alpha is the angular acceleration. We have:

\tau=(0.65kg*m^2)(29.5\frac{rad}{s^2})\\\tau=19.18N*m

Torque is the vector product of the position vector of the point at which the force is applied by the force vector:

\vec{\tau}=\vec{r}\times \vec{F}

Since the effective lever arm is perpendicular to the force, the angle between them is 90^\circ. The magnitud of this vector product is defined as:

\tau=rFsen\theta.

Solving for F and replacing the known values:

F=\frac{\tau}{rsen\theta}\\F=\frac{19.18N*m}{1.9m(sen90^\circ)}\\F=10.09N

8 0
3 years ago
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