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natulia [17]
3 years ago
6

A 7.00- kg bowling ball moves at 3.00 m/s. How fast musta

Physics
1 answer:
ratelena [41]3 years ago
6 0

Answer:

Ping Pong ball move at velocity 160.4 m/s

Explanation:

given data

mass m1 = 7 kg

velocity v1 = 3 m/s

mas m2 = 2.45 g = 2.45 × 10^{-3} kg

same kinetic energy

to find out

How fast Ping Pong ball move (v2)

solution

we know same KE

so

\frac{1}{2}* m1* v1^{2} = \frac{1}{2}* m2* v2^{2}   ...........1

so v2 will be

v2 = \sqrt{\frac{m1*v1^2}{m2} }    .............2

put here value in equation 2 we get v2

v2 = \sqrt{\frac{7*3^2}{2.45*10^{-3}}}

v2 = 160.4

so Ping Pong ball move at velocity 160.4 m/s

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What happens in a tug of war if the net forces are balanced and why?
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Answer:

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A turntable is designed to acquire an angular velocity of 32.4 rev/s in 0.5 s, starting from rest.
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3 0
2 years ago
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The High Speed Industrial Drill With Diameter Of 98 Cm Develops 5.85hp At 1900 Rpm. What Torque And Force Is Applied To The Dril
STatiana [176]

Answer:

The torque applied by the drill bit is T = 16.2 Nm and the cutting force of the drill bit is F = 33 N.

Explanation:

Given:-

- The diameter of the drill bit, d = 98 cm

- The power at which drill works, P = 5.85 hp

- The rotational speed of drill, N = 1900 rpm

Find:-

What Torque And Force Is Applied To The Drill Bit?

Solution:-

- The amount of torque (T) generated at the periphery of the cutting edges of the drilling bit when it is driven at a power of (P) horsepower at some rotational speed (N).

- The relation between these quantities is given:

                         T = 5252*P / N

                         T = 5252*5.85 / 1900

                         T = 16.171 Nm

- The force (F) applied at the periphery of the drill bit cutting edge at a distance of radius from the center of drill bit can be determined from the definition of Torque (T) being a cross product of the Force (F) and a moment arm (r):

                          T = F*r

Where,   r = d / 2

                          F = 2T / d

                          F = 2*16.171 / 0.98

                          F = 33 N

Answer: The torque applied by the drill bit is T = 16.2 Nm and the cutting force of the drill bit is F = 33 N.

4 0
3 years ago
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In a controlled experiment, which variable does the investigator change?
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Answer:

The manipulated variable is also known as the independent variable

Explanation:

When remembering this remember independent as in you independently change the outcome

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