Answer:
thursday
Step-by-step explanation:
Do whats in the parenthesis first......add the 6.1 + 12
<span> 1/3(2x - 3) + 1 = 1/4(3x + 5) - 2
2x/3 - 3/3 + 1 = 3x/4 + 5/4 - 2
2x/3 - 1 + 1 = 3x/4 + 5/4 - 2
2x/3 - 3x/4 - 0 = 3x/4 - 3x/4 + 5/4 - 2
2x*4/3*4 - 3x*3/4*3 = 0 + 5*1/4*1 - 2*4/1*4
8x/12 - 9x/12 = 5/4 - 8/4
(8x - 9x)/12 = (5 - 8)/4
-x/12 = -3/4
-x/12 * 12 = -3/4 * 12
-x = -36/4
-x * -1 = -36/4 * -1
x = 36/4
x = 9
Done
For check the answer
let x = 9
1/3(2[9] - 3) + 1 = 1/4(3[9] + 5) - 2
1/3(18 - 3) + 1 = 1/4(27 + 5) - 2
1/3(15) + 1 = 1/4(32) - 2
15/3 + 1 = 32/4 - 2
15/3 + 3/3 = 32/4 - 8/4
18/3 = 24/4
6 = 6
therefor
x = 9 is a correct answer</span>
If the jug holds only 3 7/2 ounces [13/2 ounces) of juice, the number of 2 1/2 oz. cups that can be filled is
13
----
2
------- = 13/5 cups, or 2 3/5 cups.
5
---
2
I suspect you have copied down your numbers incorrectly. Try again.
Answer:
Hi there!
I might be able to help you!
It is NOT a function.
<u>Determining whether a relation is a function on a graph is relatively easy by using the vertical line test. If a vertical line crosses the relation on the graph only once in all locations, the relation is a function. However, if a vertical line crosses the relation more than once, the relation is not a function</u>. <u>X = y2 would be a sideways parabola and therefore not a function.</u> Good test for function: Vertical Line test. If a vertical line passes through two points on the graph of a relation, it is <em>not </em>a function. A relation which is not a function. The x-intercept of a function is calculated by substituting the value of f(x) as zero. Similarly, the y-intercept of a function is calculated by substituting the value of x as zero. The slope of a linear function is calculated by rearranging the equation to its general form, f(x) = mx + c; where m is the slope.
A relation that is not a function
As we can see duplication in X-values with different y-values, then this relation is not a function.
A relation that is a function
As every value of X is different and is associated with only one value of y, this relation is a function.
Step-by-step explanation:
It's up there!
God bless you!
