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3 years ago

Write a related subtraction fact for 7 + 3 = 10

Mathematics

2 answers:

telo118 [61]3 years ago

5 0

10-3=7 Hope this helps

Svetllana [295]3 years ago

5 0

10-3=7 or 10-7=3
Hope this helps.

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.86971 rounded to the 10th

skelet666 [1.2K]

Answer:

Step-by-step explanation:

If the number behind that place is 5 or greater than you round up one but if it is 4 or below than you keep the number the same.

7 0

3 years ago

Help due Monday......

pantera1 [17]

Step-by-step explanation:

5) 2.4×10^-5 / 4.5×10^-11

2.4×10^-5= 0.000024
4.5×10^-11= 0.000000000045

=0.000024/0.000000000045

=24/1 × 1,000,000/45

=24,000,000/45

=533,333.33°

=5.33333°×10^5

**NOT SURE ABOUT THIS QUESTION

6) (4,-2)

7) --------

8)

2x + 3 = 5x - 2

2x - 5x = - 2 - 3
-3x = -5
x = -5/-3
x = 1.66°

6x + 4 = 6x + 4

6x - 6x = 4 - 4
0x = 0

2 (2x + 3) = 8x - 2

4x + 6 = 8x - 2
4x - 8x = -2 - 6
-4x = -8
x = -8/-4
x = 2

-3x + 2 = -3x + 5

-3x + 3x = 5 - 2
0x = 3

Letter be has no solution because it is broken down as "0x = 0"

6 0

3 years ago

Does anyone add me on hangout boys and girls anyone myself sahil from jharkhand class 9

bazaltina [42]

Answer: Hm, this sounds a bit out of order I hope you use better grammar and please ask a question not a comment

4 0

3 years ago

Solve the Anti derivative.

Alex Ar [27]

Answer:

$\displaystyle \int {\frac{1}{9x^2+4}} \, dx = \frac{1}{6}arctan(\frac{3x}{2}) + C$

General Formulas and Concepts:

Algebra I

Factoring

Calculus

Antiderivatives - integrals/Integration

Integration Constant C

U-Substitution

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Trig Integration: $\displaystyle \int {\frac{du}{a^2 + u^2}} = \frac{1}{a}arctan(\frac{u}{a}) + C$

Step-by-step explanation:

Step 1: Define

$\displaystyle \int {\frac{1}{9x^2 + 4}} \, dx$

Step 2: Integrate Pt. 1

[Integral] Factor fraction denominator: $\displaystyle \int {\frac{1}{9(x^2 + \frac{4}{9})}} \, dx$
[Integral] Integration Property - Multiplied Constant: $\displaystyle \frac{1}{9} \int {\frac{1}{x^2 + \frac{4}{9}}} \, dx$

Step 3: Identify Variables

Set up u-substitution for the arctan trig integration.

$\displaystyle u = x \\ a = \frac{2}{3} \\ du = dx$

Step 4: Integrate Pt. 2

[Integral] Substitute u-du: $\displaystyle \frac{1}{9} \int {\frac{1}{u^2 + (\frac{2}{3})^2} \, du$
[Integral] Trig Integration: $\displaystyle \frac{1}{9}[\frac{1}{\frac{2}{3}}arctan(\frac{u}{\frac{2}{3}})] + C$
[Integral] Simplify: $\displaystyle \frac{1}{9}[\frac{3}{2}arctan(\frac{3u}{2})] + C$
[integral] Multiply: $\displaystyle \frac{1}{6}arctan(\frac{3u}{2}) + C$
[Integral] Back-Substitute: $\displaystyle \frac{1}{6}arctan(\frac{3x}{2}) + C$