Using derivatives, it is found that the x-values in which the slope belong to the interval (-1,1) are in the following interval:
(-15,-10).
<h3>What is the slope of the tangent line to a function f(x) at point x = x0?</h3>
It is given by the derivative at x = x0, that is:
.
In this problem, the function is:

Hence the derivative is:

For a slope of -1, we have that:
0.4x + 5 = -1
0.4x = -6
x = -15.
For a slope of 1, we have that:
0.4x + 5 = 1.
0.4x = -4
x = -10
Hence the interval is:
(-15,-10).
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Answer:
The system of equations has one solution at (-4, 4).
Step-by-step explanation:
We are given the system of equations:

We can use elimination to solve this system. We need to multiply the second equation by -5 so we can cancel out our x-terms.

Therefore, our system now becomes:

Now, we can add these two equations together and solve for y.

Now, we can substitute our value for y into one of the equations and solve for x.

Therefore, our final solution is (-4, 4).
Answer:
Step-by-step explanation:
Hello, please consider the following.

Thank you