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Reptile [31]
3 years ago
6

Which expression has the same value as 3,648 - 1,223? A. 3,000 - 1,000 + 40 - 20 + 8 - 3 + 6 - 2 B. 3,000 - 1,000 + 600 - 200 +

40 - 20 + 8 - 3 C. 3,000 - 1,000 + 600 - 200 + 8 - 3 + 3 - 2 D. 3,000 - 1,000 + 600 - 200 + 80 - 30 + 4 - 2
Mathematics
1 answer:
natulia [17]3 years ago
7 0

Answer:

B

Step-by-step explanation:

3000-1000 = 2000

600-200 = + 400

40 - 20 = + 20

8 - 3 = + 5

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you are building a rectangular wading pool you want the area of the bottom to be 90 ft squared you want the length of the pool t
Sindrei [870]
L=2W+3, A=LW, using L from the first in the second gives you:

A=(2W+3)W

A=2W^2+3W, and we are told A=90 so

2W^2+3W=90

2W^2+3W-90=0

2W^2-12W+15W-90=0

2W(W-6)+15(W-6)=0

(2W+15)(W-6)=0, since W>0 for all real possibilities, 

W=6ft, and since L=2W+3

L=15ft

So the pool will be 6 ft wide by 15 ft long.
5 0
3 years ago
If (1)=3 and f(n)=f(n-1)-1 then find the value of f(6)
katrin [286]

Answer:

f(1) = 3

f(n) = f(n-1) - 1

Otherwise,

f(n) = f(1) - (n-1)

=> f(6) = 3 - 5 = -2

Hope this helps!

:)

8 0
3 years ago
Helllpppppppppp please someone.?????
Liula [17]

Answer:

(-5,5)

Step-by-step explanation:

Multiply the first equation by -2,and multiply the second equation by 1.

−2(x+5y=20)

1(2x−7y=−45)

Becomes:

−2x−10y=−40

2x−7y=−45

Add these equations to eliminate x:

−17y=−85

Then solve−17y=−85for y:

(Divide both sides by -17)

y=5

x+5y=20

Substitute  5 for y in x+5y=20:

x+(5)(5)=20

x+25=20(Simplify both sides of the equation)

x+25+−25=20+−25(Add -25 to both sides)

x=-5

6 0
3 years ago
HELP ME NEED TO SUBMIT IN 6 MINUTES<br> WILL MARK BRAINLIEST FOR CORRECT ANSWER
agasfer [191]

Answer:c

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
AT&amp;T would like to test the hypothesis that the proportion of 18- to 34-year-old Americans that own a cell phone is less tha
Vera_Pavlovna [14]

Answer:

The null and alternative hypothesis can be written as:

H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2< 0

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the proportion of 18- to 34-year-old Americans that own a cell phone is less than the proportion of 35- to 49-year-old Americans.

This claim will be reflected in the alternnative hypothesis, that will state that the population proportion 1 (18 to 34) is significantly smaller than the population proportion 2 (35 to 49).

On the contrary, the null hypothesis will state that the population proportion 1 is ot significantly smaller than the population proportion 2.

Then, the null and alternative hypothesis can be written as:

H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2< 0

The significance level is assumed to be 0.05.

The sample 1, of size n1=200 has a proportion of p1=0.63.

p_1=X_1/n_1=126/200=0.63

The sample 2, of size n2=175 has a proportion of p2=0.68.

p_2=X_2/n_2=119/175=0.68

The difference between proportions is (p1-p2)=-0.05.

p_d=p_1-p_2=0.63-0.68=-0.05

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{126+119}{200+175}=\dfrac{245}{375}=0.653

The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.653*0.347}{200}+\dfrac{0.653*0.347}{175}}\\\\\\s_{p1-p2}=\sqrt{0.001132+0.001294}=\sqrt{0.002427}=0.049

Then, we can calculate the z-statistic as:

z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{-0.05-0}{0.049}=\dfrac{-0.05}{0.049}=-1.01

This test is a left-tailed test, so the P-value for this test is calculated as (using a z-table):

\text{P-value}=P(z

As the P-value (0.1554) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the proportion of 18- to 34-year-old Americans that own a cell phone is less than the proportion of 35- to 49-year-old Americans.

5 0
3 years ago
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