D.perpendicular cross section of a pyramid cone
Answer:
here's your answer buddy
Step-by-step explanation:
In LMN - LMO
LM=LM {common} S
NL=MO { given} S
LO=MN {given} S
therefore by SSS criteria we can say that triangle LMN=LMO
the above mentioned answer is 100% correct
so please don't doubt
mark as brainliest if you wish
thank you
Answer:
it is five
Step-by-step explanation:
5v-2=8 then v=x2 because 5x2=10-2=8
so 7v-9=5
Answer:
120.105m^2
Step-by-step explanation:
Given data
Diameter of circular bed= 24+3m = 27m
radius= 27/2= 13.5
m
Diameter of side walk = 12
radius= 24= 12
m
Hence the area of the sidewalk is
Area= area of circular bed- area of side walk
Area=πR^2-πr^2
Area=π(R^2-r^2)
Area=π(13.5^2-12^2)
Area= 3.14(182.25-144)
Area= 3.14(38.25)
Area=120.105m^2
Hence the area of the side walk is 120.105m^2
Answer:
D
Step-by-step explanation:
If n=minimum number of required words and the essay is 175 words long which is 5 times more words than the minimum number of required words, you multiply n with 5 and equate to 175. To get n, you divide 175 with 5(175/5) which is 35 words.
