Answer:
Fixed rate is $60.
Step-by-step explanation:
Let us consider per student charge be 'x'.
Let us consider fixed rate be 'b'
Given:
I rent a gym for $150 for 30 students.
So we can say that;
Total amount is equal to sum of number of students multiplied by per student charge and fixed rate.
framing in equation form we get;
Also Given:
another time I rent the gym for $270 for 70 students.
So we can say that;
Total amount is equal to sum of number of students multiplied by per student charge and fixed rate.
framing in equation form we get;
Now we will subtract equation 1 from equation 2 we get;
Dividing both side by 40 we get;
Now we will substitute the value of x in equation 1 we get;
So we can say that the equation can be written as;
Hence we can say that fixed rate is $60 and per student charge is $3.
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Answer:
R(p) = -3500p^2 +48000p . . . revenue function
$6.86 . . . price for maximum revenue
Step-by-step explanation:
The 2-point form of the equation for a line can be used to find the attendance function.
y = (y2 -y1)/(x2 -x1)(x -x1) +y1
y = (27000 -20000)/(6 -8)(x -8) +20000
y = -3500(x -8) +20000
y = 48000 -3500x . . . . y seats sold at price x
The per-game revenue is the product of price and quantity sold. In functional form, this is ...
R(p) = p(48000-3500p)
R(p) = -3500p^2 +48000p . . . per game revenue
__
Revenue is maximized when its derivative is zero.
R'(p) = -7000p +48000
p = 48/7 ≈ 6.86
A ticket price of $6.86 would maximize revenue.
2, 4, -1 would be the coefficients since a coefficient is the number that goes before the x
3x^2-7x-8
explanation:3x^2+8x-15x-8
=3x^2-7x-8
Answer:
0.355
Step-by-step explanation:
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