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4 years ago

To make 3.7 a whole number, multiply by ?

Mathematics

2 answers:

Anon25 [30]4 years ago

6 0

3.7 x 10 = 37
you must multiply by 10 to remove the point

MArishka [77]4 years ago

4 0

By 10.
3.7 X 10 = 37 (in a calculator)

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Create an equation to solve for x, then solve to find its value.

Amanda [17]

Answer:

Equation: x + 16 + 13 + x = 21 ; x = -4

Step-by-step explanation:

x + 16 + 13 + x = 21 (Given)

2x + 29 = 21 (Added like terms)

2x = -8 (Subtracted 29 on both sides)

x = -4 (Divided 2 on both sides)

8 0

3 years ago

Read 2 more answers

You know that in a specific population of rainbow trout 15% of the individuals carry intestinal parasites. Assume you obtain a r

kicyunya [14]

Answer:

a) 0.2316 = 23.16% probability that 0 carry intestinal parasites.

b) 0.4005 = 40.05% probability that at least two individuals carry intestinal parasites.

Step-by-step explanation:

For each trout, there are only two possible outcomes. Either they carry intestinal parasites, or they do not. Trouts are independent. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

You know that in a specific population of rainbow trout 15% of the individuals carry intestinal parasites.

This means that $p = 0.15$

Assume you obtain a random sample of 9 individuals from this population:

This means that $n = 9$

a. Calculate the probability that __ (last digit of your ID number) carry intestinal parasites.

Last digit is 0, so:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{9,0}.(0.15)^{0}.(0.85)^{9} = 0.2316$

0.2316 = 23.16% probability that 0 carry intestinal parasites.

b. Calculate the probability that at least two individuals carry intestinal parasites.

This is

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{9,0}.(0.15)^{0}.(0.85)^{9} = 0.2316$

$P(X = 1) = C_{9,1}.(0.15)^{1}.(0.85)^{8} = 0.3679$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.2316 + 0.3679 = 0.5995$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.5995 = 0.4005$

0.4005 = 40.05% probability that at least two individuals carry intestinal parasites.

5 0

3 years ago

Which transformations can be used to show that circle P is similar to circle Q?

Olin [163]

<span>The Selected correct answers are.

Circle Q is a dilation of circle P with a scale factor of 7.

Circle Q is a translation of circle P, 6 units up.</span>

7 0

3 years ago

Read 2 more answers

Three more then eight times J

alexgriva [62]

Answer: 8j+3

Step-by-step explanation:

Hope this helps

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3 years ago

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What expression is equivalent to 1/3 x -1/5