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butalik [34]
3 years ago
8

Write Lewis formulas that follow the octet rule for C2H4

Chemistry
1 answer:
umka21 [38]3 years ago
7 0
Hello there!

This is an interesting thing I did last year in my Sophomore year.

Let me try this out!

First, we wanna start by drawing a standard structure with carbon in the middle, as hydrogen can only form one bond. (Please see pictue #1)

We know that the center carbon has too many bonds (maximum of 4), so we will shift two hydrogen over to the other carbon. (See picture #2)

Now each carbon has too few bonds, so we will make a double bond between them.

The last picture is the correct structure of C2H4, ethylene. The octet rule is kept.


I am terrible when it comes to drawing things. I hope this helps~!



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Answer:

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Explanation:

1) Identify the parent chain and name it like an alkane.

• The longest chain of carbons, which consists of the functional group (which is the alkyne group in this case: C≡C).

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2) Now, identify the location of the functional group.

• The location number of the functional group should be as low as possible. Thus although we could count from the right, we start counting from the left since the functional group is closer to the left. From the left, the functional group would be at carbon 8 while from the left, it is on carbon 3.

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3) Lastly, add in the name of the branch.

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• Identify the location number of the branch by counting the number of carbons in the same direction as when we counted the location number of the functional group. The methyl branch has a location number of 7.

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A) This option is incorrect as there are only 8 carbons in the parent chain. Although there are 9 carbons in total, the 9th carbon is taken care of in '7-methyl'.

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C) Since the functional group is an alkyne, the word 'octane' should be 'octyne' instead.

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