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Lina20 [59]
3 years ago
14

This dipeptide is designated as: there is a structure for h3nchcnhchco with ch2oh group attached to the first (from left to righ

t) carbon, two oxygen atoms attached to the second and fourth carbons by double bonds, and ch2sh group attached to the third carbon. nitrogen has a charge of 1 plus. oxygen atom, which is attached to the fourth carbon by a single bond, has a charge of 1 minus.

Chemistry
1 answer:
oksian1 [2.3K]3 years ago
4 0

A dipeptide is formed when 2 amino acids are joined together by a peptide linkage.

Each amino acid molecule contains an amino group ( -NH₂) and a carboxyl ( -COOH) group. During peptide formation, a carboxyl group of one amino acid reacts with amino group of the other , resulting in the formation of a linkage known as "peptide linkage". A water molecule is also eliminated in this reaction.

A general peptide formation reaction can be written as

NH_{2}-CH_{2}-COOH + H_{2}N-CH_{2}-COOH \rightarrow NH_{2}-CH_{2}-CONH-CH_{2}-COOH +H_{2}O

In the above reaction, we can see a peptide linkage ( -CONH-) getting formed between 2 amino acid molecules.

In the given molecule the peptide linkage is shown by drawing a box around it. Please refer to the attached image.

If we want to know the amino acid molecules from which this peptide is formed, we will simply break the CO-NH bond.

We will add -OH group to CO part and -H to NH part to get 2 amino acid molecules as shown in the picture.

The two amino acids thus formed are Serine & Cysteine.

Serine is designated as "Ser" and Cysteine is designated as "Cys"

Therefore the given dipeptide is designated as "Ser-Cys"

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It's describe as Ethylene
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A sample of raw mining ore contains a hydrated salt called copper sulfate tetrahydrate, CuSO4.4H2O, along with other impurities.
julsineya [31]

Answer:

88.5 % of the raw ore is CuSO4*4H2O

Explanation:

Step 1: Data given

Mass of the ore = 10.854 grams

Mass of water = 2.994 grams

Step 2: Calculate moles H2O

Moles H2O = mass H2O / molar mass H2O

Moles H2O = 2.994 grams / 18.02 g/mol

Moles H2O = 0.166 moles

Step 3: Calculate moles CuSO4*4H2O

For 1 mol CuSO4*4H2O we have 4 moles H2O

For 0.166 moles H2O we have 0.166/4 = 0.0415 moles CuSO4*4H2O

Step 4: Calculate mass CuSO4*4H2O

Mass CuSO4*4H2O = moles * molar mass

Mass CusO4*4H2O = 0.0415 moles * 231.67 g/mol

Mass CuSO4*4H2O = 9.61 grams

Step 5: Calculate mass % of CuSO4*4H2O

Mass % = (9.61 grams / 10.854 grams )*100 %

Mass % = 88.5 %

88.5 % of the raw ore is CuSO4*4H2O

4 0
4 years ago
Please help I’ll mark you as brainliest if correct!
Brums [2.3K]

Answer:

C.

Explanation:

Gas molecules are diatomic which means it usually comes in 2.

So, H2(g)+O2(g) is H2O (l)

The first one is OH(hydroxide, not water)

Second one is not gas(not diatomic)

Answer is C.

8 0
3 years ago
How many molecules are in 3.6 grams of NaCl? Question options:
Levart [38]

Answer:

\boxed {\boxed {\sf 3.7 * 10^{22} \ molecules \ NaCl}}

Explanation:

We are asked to find how many molecules are in 3.6 grams of sodium chloride.

<h3>1. Convert Grams to Moles </h3>

First, we convert grams to moles using the molar mass. These values are equivalent to atomic masses on the Periodic Table, but the units are grams per moles instead of atomic mass units. Look up the molar masses of the individual elements: sodium and chlorine.

  • Na: 22.9897693 g/mol
  • Cl: 35.45 g/mol

There are no subscripts in the chemical formula (NaCl), so we simply add the 2 molar masses.

  • NaCl: 22.9897693 + 35.45 = 58.4397693 g/mol

Now we will convert using dimensional analysis. First, set up a ratio using the molar mass.

\frac {58.4397693 \ g \ NaCl}{ 1 \ mol \ NaCl}

We are converting 3.6 grams to moles, so we must multiply the ratio by this value.

3.6 \ g \ NaCl *\frac {58.4397693 \ g \ NaCl}{ 1 \ mol \ NaCl}

Flip the ratio so the units of grams of sodium chloride cancel.

3.6 \ g \ NaCl *\frac { 1 \ mol \ NaCl}{58.4397693 \ g \ NaCl}

3.6  *\frac { 1 \ mol \ NaCl}{58.4397693}

\frac { 3.6}{58.4397693} \ mol \ NaCl

0.06160188589 \ mol \ NaCl

<h3>2. Convert Moles to Molecules </h3>

Next, we convert moles to molecules using Avogadro's Number. This is 6.022 × 10²³ and it tells us the number of particles (atoms, molecules, formula units, etc). In this case, the particles are molecules of sodium chloride. Let's set up another ratio.

\frac {6.022 \times 10^{23} \ molecules \ NaCl}{ 1 \ mol \ NaCl}

Multiply by the number of moles we calculated.

0.06160188589 \ mol \ NaCl * \frac{6.022 \times 10^{23} \ molecules \ NaCl}{1 \ mol \ NaCl}

The units of moles of sodium chloride cancel.

0.06160188589 * \frac{6.022 \times 10^{23} \ molecules \ NaCl}{1 }

3.70966557*10^{22} \ molecules \ NaCl

<h3>3. Round </h3>

The original measurement of grams (3.6) has 2 significant figures, so our answer must have the same. For the number we found, that is the tenths place. The 0 in the hundredth place tells us to leave the 7 in the tenth place.

3.7 * 10^{22} \ molecules \ NaCl

There are 3.7 * 10^{22} \ molecules \ NaCl in 3.6 grams and the correct answer is choice D.

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What is the total amount of kinetic and potential energy of a substance?
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Answer:

I <em><u>THINK mechanical energy</u></em>

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