<h3>
Answer:</h3>
Mole ratio of D to A is 1 : 4
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Explanation:</h3>
We are given the generic chemical equation;
4A + B → C + D
We are supposed to determine the mole ratio of D to A
What is mole ratio?
- Mole ratio is the ratio of the number of moles of reactants or products in a chemical reaction.
- We determine the mole ratio using the coefficients of reactants or products in question.
For example;
- In the equation, 4A + B → C + D, the coefficient of A is 4 while the coefficient of D is 1.
- This means, 4 moles of A reacts with 1 mole of b to produce 1 mole of C and 1 mole of D
- Thus, mole ratio of D to A is 1 : 4
Answer:
The number of moles of CH₄ that will remain is 7.5 moles
Explanation:
Complete combustion reaction of oxygen and methane is given as;
CH₄ + 2O₂ → CO₂ + 2H₂O
comparing the number of moles of methane and oxygen in the reaction above, the amount of methane used in the reaction is calculated as follows;
2 moles of O₂ -----------> 1 mole of CH₄
7 moles of O₂ ------------> x moles of CH₄
x = 7 / 2
x = 3.5 moles of CH₄
Total moles of CH₄ in the reactor = 11.0 moles
The number of moles that will remain = 11.0 moles - 3.5 moles
The number of moles that will remain = 7.5 moles
Therefore, the number of moles of CH₄ that will remain is 7.5 moles
Answer:
Presence of lone pairs of electrons
Explanation:
According to VSEPR theory, the presence of lone pairs caused increased repulsion of electron pairs on the valence shell of the centeral atom of the molecule. This decreases or distorts the bond angle. The decrease in bond ange depends on the number of lone pairs present on the valence shell of the central atom of the molecule. Ammonia has only one lone pair hence the bond angle is 107°, water has two lone pairs and the bond angle is 104°. Compare this this with the bond angle of 109° in methane which has only bond pairs and no lone pairs.
Answer:
correct answers:
objecting to a local and consent bill
chubbing
filibuster
incorrect answers:
amending legislation
vetoing legislation
Explanation:
Use the following equations to fill the chart.
E = hf
where
h = 6.63 x 10⁻³⁴ J/s, Planck's constant
f = frequency Hz
E = quanta of energy, J
c = fλ
where
c = 3 x 10⁸ m/s, the velocity of light
λ = wavelength, m
If energy is given in J/mmol, divide by Avogadro's number, N = 6.02 x 10²³, to convert it to J.
The completed table is shown below.
