The decomposition time : 7.69 min ≈ 7.7 min
<h3>Further explanation</h3>
Given
rate constant : 0.029/min
a concentration of 0.050 mol L to a concentration of 0.040 mol L
Required
the decomposition time
Solution
The reaction rate (v) shows the change in the concentration of the substance (changes in addition to concentrations for reaction products or changes in concentration reduction for reactants) per unit time
For first-order reaction :
[A]=[Ao]e^(-kt)
or
ln[A]=-kt+ln(A0)
Input the value :
ln(0.040)=-(0.029)t+ln(0.050)
-3.219 = -0.029t -2.996
-0.223 =-0.029t
t=7.69 minutes
Ok measure atoms the answer is B
The answer is 6 moles of water will be produced.
Answer:
53% aluminium is present.
Explanation:
Given data:
Mass of aluminium in bauxite = 108 g
Total mass of sample = 204 g
Percentage of aluminium = ?
Solution:
Formula:
Percentage = Mass of aluminium / total mass of sample× 100
Now we will put the values in formula:
Percentage = 108 g/204 × 100
Percentage = 0.53 × 100
Percentage = 53%
So in given 204 g of bauxite there is 53% aluminium is present.
