Answer:
- Current market value of silver produced in the experiment = $0.2763
- Check Explanation for the appearance of leftover copper wire used in the experiment.
Explanation:
Price of Silver on today's market = $15.34 per troy ounce
Amount of Silver produced in the experiment = 0.56 g
31.1 g = 1 troy ounce
0.56 g = (0.56/31.1) = 0.01801 troy ounce
1 troy ounce = $15.34
0.01801 troy ounce = 0.01801 × $15.34 = $0.2763
The original reaction to extract the silver is one between Copper metal and the Silver Nitrate.
The Copper metal dissolves in the Silver Nitrate to give Copper Nitrate thereby displacing the Silver ion to become silver metal which we just valued above. But copper nitrate is a blue solution, So, it is a good estimate to say that the entire solution changed to that blue colour and the appearance of the leftover copper metal is colour blue. The silver metal forms as fractal-like crystals on this leftover copper.
Hope this Helps!!!
Answer:
Explanation:
B.
BALANCED. 7C, 16H, and 22O on each side of equation.
A.
NOT BALANCED. 7C on left and 6C on right.
C.
NOT BALANCED. 16H on left and 10H on right.
D.
NOT BALANCED. 7C on left and 14C on right.
In nuclear fission heavier elements are split to make lighter elements whilst releasing energy. An atom, its nucleus to be more specific, is bombarded with neutrons. The nucleus becomes unstable and it starts to split/decay. It creates the fusion products. Neutrons and lighter elements are released; the neutrons from the nuclei of the atom(s) being split.
Taking into account the reaction stoichiometry, you can observe that:
- one mole of Ca₃P₂ produces 2 mol of PH₃.
- the mole ratio between phosphine and calcium phosphide is 2 mol PH₃ over 1 mol Ca₃P₂.
<h3>Reaction stoichiometry</h3>
In first place, the balanced reaction is:
Ca₃P₂ + 6 H₂O → 3 Ca(OH)₂ + 2 PH₃
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- Ca₃P₂:1 mole
- H₂O: 6 moles
- Ca(OH)₂: 3 moles
- PH₃: 2 moles
The molar mass of the compounds is:
- Ca₃P₂: 182 g/mole
- H₂O: 18 g/mole
- Ca(OH)₂: 74 g/mole
- PH₃: 34 g/mole
Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
- Ca₃P₂: 1 mole ×182 g/mole= 182 grams
- H₂O: 6 moles× 18 g/mole= 108 grams
- Ca(OH)₂: 3 moles ×74 g/mole= 222 grams
- PH₃: 2 moles ×34 g/mole= 68 grams
<h3>Correct statements</h3>
Then, by reaction stoichiometry, you can observe that:
- one mole of Ca₃P₂ produces 2 mol of PH₃.
- the mole ratio between phosphine and calcium phosphide is 2 mol PH₃ over 1 mol Ca₃P₂.
Learn more about the reaction stoichiometry:
<u>brainly.com/question/24741074</u>
<u>brainly.com/question/24653699</u>
Use M1V1 = M2V2 to solve
3(V1) = 2.8 * 1.6
3(V1) = 4.48
V1 = 1.493 L of stock solution
