Given:
The frequency distribution table.
To find:
The mean average score on a test.
Solution:
The frequency distribution table is
x a xa
y b yb
z c zc
Sum a+b+c xa+yb+zc
Now, the mean average score on the test is
Therefore, the mean average score on the test is 
.
Answer:
The exact interest on $5,870 at 12% is $410.9
Step-by-step explanation:
From the information provided we know that
Principal amount: $5,870
Interest rate: 12% -> 0.12
Time: 7 months (From June to December)
When you know the principal amount, the rate, and the time, the amount of interest can be calculated by using the formula:
where P is principal, r is the rate of interest and t is the time in years.
We need to convert the 7 months into 1 year.
Now we can use the above formula
Therefore the exact interest on $5,870 at 12% is $410.9
Answer:
I don't know if I understood the question correctly, but this is what I have...
Step-by-step explanation:
If the "x" is a variable:
(2x-3)-(1-1)=
2x-3
If th "x" is a multiplication sign:
(2x-3)-(1-1)=
-6-0=
-6
i hope this helps
Let Xi be the random variable representing the number of units the first worker produces in day i.
Define X = X1 + X2 + X3 + X4 + X5 as the random variable representing the number of units the
first worker produces during the entire week. It is easy to prove that X is normally distributed with mean µx = 5·75 = 375 and standard deviation σx = 20√5.
Similarly, define random variables Y1, Y2,...,Y5 representing the number of units produces by
the second worker during each of the five days and define Y = Y1 + Y2 + Y3 + Y4 + Y5. Again, Y is normally distributed with mean µy = 5·65 = 325 and standard deviation σy = 25√5. Of course, we assume that X and Y are independent. The problem asks for P(X > Y ) or in other words for P(X −Y > 0). It is a quite surprising fact that the random variable U = X−Y , the difference between X and Y , is also normally distributed with mean µU = µx−µy = 375−325 = 50 and standard deviation σU, where σ2 U = σ2 x+σ2 y = 400·5+625·5 = 1025·5 = 5125. It follows that σU = √5125. A reference to the above fact can be found online at http://mathworld.wolfram.com/NormalDifferenceDistribution.html.
Now everything reduces to finding P(U > 0) P(U > 0) = P(U −50 √5125 > − 50 √5125)≈ P(Z > −0.69843) ≈ 0.757546 .
