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3 years ago

Which of the following is a solution of the equation 9- 2x=-1? 04 05 04 0-5

Mathematics

2 answers:

8_murik_8 [283]3 years ago

8 0

Answer:

the answer is 5

Step-by-step explanation:

9-2x=-1. you subtract the 9 from both sides, giving you -2x=-10. then you divide the -10 by -2 which gives you 5

netineya [11]3 years ago

6 0

The answer is 5. -2x=-10. x=5.

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How many solutions does the polynomial equation ( x+8)2( x-1) = 0

Olin [163]

Answer:

-8 and 1

Step-by-step explanation:

8 0

3 years ago

I am having trouble solving this question. please give me a detailed and elaborate answer and also please attach the plotted gra

serious [3.7K]

Answer:

$ 2000

Step-by-step explanation:

Find the equation. You find the gradient by using the gradient formula (rise/run)

that would be

1600 - 800 over 40 - 20

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3 0

3 years ago

Read 2 more answers

35. Two variables, x and y, appear to be exponentially related. The regression equation for ln y on x is ln y = 1.7 + .45x. What

GrogVix [38]

Answer:

$y=7.57$

Step-by-step explanation:

Two variables, x and y, appear to be exponentially related. The regression equation for ln y on x is $ln y = 1.7 + .45x$

we need to predict the value of y when x=0.72

plug in the value of x in the given equation

$ln y = 1.7 + .45x$

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$ln y = 1.7 + 0.324$

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$y=7.57$

7 0

3 years ago

(4 ² +24) = |(3 - 7) - 16|=<br> 3<br> 5<br> 1<br> 2

STALIN [3.7K]

Answer:

The equality is not true.

Step-by-step explanation:

$(4^2 +24) = |(3 - 7) - 16|$

$(16 +24) = |(3 - 7) - 16|$

$40 = |(3 - 7) - 16|$

$40 = |(- 4) - 16|$

$40 = |-20|$

$40 = 20$

But

$40 \neq 20$

6 0

3 years ago

Solve: 10 2/3+2h≤4 1/3

PtichkaEL [24]

Answer:

$\large\boxed{h\leq-\dfrac{19}{6}\to h\in\left(-\infty,\ -\dfrac{19}{6}\right]}$

Step-by-step explanation:

$\text{First convert the mixed numbers to the improper fractions:}\\\\10\dfrac{2}{3}=\dfrac{10\cdot3+2}{3}=\dfrac{32}{3}\\\\4\dfrac{1}{3}=\dfrac{4\cdot3+1}{3}=\dfrac{13}{3}\\\\\text{Solve the inequality}\\\\10\dfrac{2}{3}+2h\leq4\dfrac{1}{3}\\\\\dfrac{32}{3}+2h\leq\dfrac{13}{3}\qquad\text{multiply both sides by 3}\\\\3\!\!\!\!\diagup^1\cdot\dfrac{32}{3\!\!\!\!\diagup_1}+3\cdot2h\leq3\!\!\!\!\diagup^1\cdot\dfrac{13}{3\!\!\!\!\diagup_1}\\\\32+6h\leq13\qquad\text{subtract 32 from both sides}\\\\6h\leq-19\qquad\text{divide both sides by 6}\\\\h\leq-\dfrac{19}{6}$

6 0

3 years ago