The magnitude of the force on the left-hand pole of the thin flexible gold chain of uniform linear density with a mass of 17.1 and, hangs between two 30.0 cm long vertical sticks, which are a distance of 30.0 cm apart will be, 0.167N.
To find the correct answer, we have to know more about the Basic forces that acts upon a body.
<h3>What is force and which are the basic forces that acts upon a body?</h3>
- A push or a pull which changes or tends to change the state or rest, or motion of a body is called Force.
- Force is a polar vector as it has a point of application.
- Positive force represents repulsion and the negative force represented attraction.
- There are 3 main forces acting on a body, such as, weight mg, normal reaction N, and the Tension or pulling force.
<h3>How to solve the problem?</h3>
- We have given that, the gold chain hangs between the vertical sticks of 30cm and the horizontal distance between then is 30cm.
- From the given data, we can find the angle (in the free body diagram, it is given as θ).
- From the free body diagram given, we can write the balanced equations of total force along y direction as,
- From the free body diagram given, we can write the balanced equations of total force along x direction as,
Thus, we can conclude that, the magnitude of force on the left-hand pole will be 0.167N.
Learn more about the Basic forces that acts upon a body here:
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Answer:
Zero angle is possible geometrically in a right triangle when its length of opposite side is equal to zero. Due to zero length of opposite side, the length of hypotenuse is absolutely equal to the length of hypotenuse.
Answer:
K' = 1777.777 J
Explanation:
Given that
m = 40 kg
v= 15 m/s
K=1000
Given that kinetic energy(K) varies with mass(m) and velocity(v)
K= C(mv²)
Where
C= Constant
m=mass
v=velocity
When
m = 40 kg ,v= 15 m/s ,K=1000
K= C(mv²)
1000 = C( 40 x 15²)
C=0.111111
When m = 40 kg and v= 20 m/s
K' = C(mv²)
K= 0.1111 x (40 x 20²)
K' = 1777.777 J
Answer: 760 N
Weight is the force acting on the body due to gravity. This weight is shown by weighing scale which measures the normal force acting against the gravitational pull when the person stands on it.
When Lucy stands on the weighing scale, net force due to gravity is
Hence, weight of Lucy is 760 N