Which is a correct example of the principle of conservation of momentum? A) reversing of a car at a dead end B) conversion of ra
2 answers:
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Answer:
The horizontal component of the velocity is 21.9 m/s.
Explanation:
Please see the attached figure for a better understanding of the problem.
Notice that the vector v and its x and y-components (vx and vy) form a right triangle. Then, we can use trigonometry to find the magnitude of vx, the horizontal component of the velocity.
To find vx, let´s use the following trigonometric rule of right triangles:
cos α = adjacent / hypotenuse
cos 5.7° = vx / 22 m/s
22 m/s · cos 5.7° = vx
vx = 21.9 m/s
The horizontal component of the velocity is 21.9 m/s.
Answer:
1) 3.9 %
2) 1,38 kg
3) 0.13 cubic meters
Explanation:
Part 1)
Calculated current = 0.180 amps
Measured current: 0.173 amps
percent error : %
Part 2)
mass1 = 1,155 kg
mass2 = 0.22 kg
Addition; 1.155 + 0.22 = 1 375 kg which should be rounded to just two decimals according to the addition rules for uncertainties:
Answer : 1,38 kg
Part 3)
Volume = 0.885 x 0.20 x 0.75 cubic meters = 0.13275 cubic meters
Notice that the smallest number of significant figures among the set of dimension given is two. Therefore, our answer should be rounded to two significant figures. That is:
Volume = 0.13 cubic meters