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Sophie [7]
3 years ago
6

Which is a correct example of the principle of conservation of momentum? A) reversing of a car at a dead end B) conversion of ra

dio waves to sound C) deforming of a balloon on being burst D) bouncing of a basketball off the board
Physics
2 answers:
Hunter-Best [27]3 years ago
3 0
I think the answer would be D.
Mars2501 [29]3 years ago
3 0
<span>Which is a correct example of the principle of conservation of momentum?

</span>
<span>D) bouncing of a basketball off the board </span>
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During a __________ year period starting at about 4.5 billion years ago, bits and pieces of metal-rich particles, rocks, and ice
Greeley [361]

During a 30-10 million year period starting at about 4.5 billion years ago, bits and pieces of metal-rich particles, rocks, and ices accumulated to form the earth.

<h3>What is the Earth?</h3>

This is referred to as a type of planet which is habitable for different types of life forms. It is also the third planet from the sun and a majority of it contains water such as oceans etc.

Earth was formed billions of years ago through the bits and pieces of metal-rich particles, rocks, and ices which was in a 30-10 million year period which therefore makes it the correct choice.

Read more about Earth here brainly.com/question/10715182

#SPJ1

3 0
1 year ago
How much work is done if you push a 200 N box across a floor with a force of 50 N for a distance of 20m
vovikov84 [41]
<h2>Answer: 1000 J</h2>

The Work W done by a Force F refers to the release of potential energy from a body that is moved by the application of that force to overcome a resistance along a path.  

It should be noted that it is a scalar magnitude, and its unit in the International System of Units is the Joule (like energy). Therefore, 1 Joule is the work done by a force of 1 Newton when moving an object, in the direction of the force, along 1 meter:  

1J=(1N)(1m)=Nm  

Now, when the applied force is constant and the direction of the force and the direction of the movement are parallel, the equation to calculate it is:  

W=(F)(d) (1)

When they are not parallel, both directions form an angle, let's call it \alpha. In that case the expression to calculate the Work is:  

W=Fdcos{\alpha} (2)

For example, in order to push the 200 N box across the floor, you have to apply a force along the distance d to overcome the resistance of the weight of the box (its 200 N).  

In this case both <u>(the force and the distance in the path) are parallel</u>, so the work W performed is the product of the force exerted to push the box F=50N by the distance traveled d. as shown in equation (1).

Hence:

W=(50N)(20m)  

W=1000Nm=1000J >>>>This is the work  

8 0
3 years ago
A circuit has a voltage drop of 54.0 V across a 30.0 o resistor that carries a current of 1.80 A. What is the power used by the
Blizzard [7]

Answer:

P = 97.2 W

Explanation:

Given that,

Voltage drop, V = 54 V

The resistance of the resistor, R = 20 Ohms

Current, I = 1.8 A

We need to find the power used by the resistor. The formula used to find the power is given by :

P = VI

Putting all the values,

P = 54 V × 1.8 A

P = 97.2 W

So, the power used by the resistor is 97.2 W.

5 0
3 years ago
Read 2 more answers
A uniform rod of length 50cm and mass 0.2kg is placed on a fulcrum at a distance of 40cm from the left end of the rod. At what d
oksano4ka [1.4K]

Answer:

x = 45 cm

Explanation:

Given that,

The length of a rod, L = 50 cm

Mass, m₁ = 0.2 kg

It is at 40cm from the left end of the rod.

We need to find the distance from the left end of the rod should a 0.6kg mass be hung to balance the rod.

The centre of mass of the rod is at 25 cm.

Taking moments of both masses such that,

15\times 0.2=x\times 0.6\\\\x=\drac{3}{0.6}\\\\x=5\ cm

The distance from the left end is 40+5 = 45 cm.

Hence, at a distance of 45 cm from the left end it will balance the rod.

5 0
3 years ago
A person wishes to heat pot of fresh water from 20°C to 100°C in order to boil water for pasta. They calculate that their pot ho
nasty-shy [4]
Given:
Water, 2 kilograms
T1 = 20 degrees Celsius, T2 = 100 degrees Celsius.  

Required:
Heat produced  

Solution:
Q (heat) = nRT = nR(T2 = T1)
Q (heat) = 2 kilograms (4.184 kiloJoules per kilogram Celsius) (100 degrees Celsius – 20 degrees Celsius)
<u>Q (heat) = 669.42 Joules
</u>This is the amount of heat produced in boiling 2 kg of water.
6 0
4 years ago
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