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White raven [17]
3 years ago
10

A forest is an ecosystem. There are many plants and animals in the forest. What is true about the plants and animals? The plants

depend on the animals. The animals depend on the plants. The plants do not depend on the animals. The animals do not depend on the plants.
Physics
2 answers:
Volgvan3 years ago
7 0

Answer:

The plants depend on animals and animals depend on plants.

Plants depend on animals for nutrients, pollination and seed dispersal. Animals are totally dependent on plants. First of all plants produce oxygen which is vital for life on earth. Then, for many animals plants are their basic food, or if plants don’t make up 100 % of their diet, plants are nevertheless essential in their food supply.

ivanzaharov [21]3 years ago
6 0

Answer:

A. The plants depend on the animals.

B. The animals depend on the plants.

Explanation:

Plants require animals to spread their seeds around the area, also known as seed dispersal. They also use the help of other animals for pollination. Bees can be used as a great example for pollination and so as butterflies, flies, etc. Some plants have seeds with barbs that stick to the animals fur. Some just simply stick to the animals paws and/or fur until dropping off to another place. Other seeds are consumed and then composed. Here's an example. A deer eats an apple. Everyone knows that apples have seeds, hence, the deer consumes the seeds. The deer will then compose the digested food along with the seeds. Now, the apple's seeds have settled in another place and will start its growth. Animals also depend on the plants. Plants are a source of food for many herbivores and omnivores. Plants also have a high nutrition, giving animals the nourishment needed. They also produce oxygen and take in carbon dioxide. This is necessary for earth and its wildlife on it.

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A missile is moving 1350 m/s at a 25.0° angle. It needs to hit a target 23,500 m away in a 55.0° direction in 10.20 s. What is d
QveST [7]

Answer:

  The target's velocity is about 1320 m/s in the direction 265.7°.

Explanation:

In order for there to be a collision between missile and target, we must have ...

  (target starting position) + (target movement) = (missile movement)

assuming the missile starts from the origin of all measurements. The missile moves 10.2 seconds before impact, so moves a distance of ...

  (10.2 s)(1350 m/s) = 13,770 m

__

We are interested in the target movement, so we can solve for that:

  (target movement) = (missile movement) - (target starting position)

In terms of meters, this is ...

  (target movement) = 13770∠25° - 23500∠55° ≈ 13467.74∠-94.3°

The target covers this distance in the same 10.2 seconds before collision, so its speed is (13467.74 m)/(10.2 s) ≈ 1320.4 m/s.

As a positive angle, the target's direction is ...

  -94.3° +360° = 265.7°

The direction of the target's velocity is 265.7°.

_____

If you're calculating this by hand, there are a couple of ways you can do it. You can convert to rectangular coordinates and back (perhaps least confusing), or you can use the law of cosines to solve the triangle, then translate angles back to the x-y coordinate plane.

Using rectangular coordinates, we have ...

  13770∠25° = 13770(cos(25°), sin(25°)) ≈ (12479.9, 5819.45)

  23500∠55° = 23500(cos(55°), sin(55°)) ≈ (13479.0, 19250.1)

Then the difference is ...

  (12479.9, 5819.45) -(13479.0, 19250.1) ≈ (-999.188, -13430.6)

and the (3rd-quadrant) angle is ...

  target direction = arctan(-13430.6/-999.188) ≈ -94.3° = 265.7°

__

The target's speed is found by dividing the distance it covers by the time it takes.

  √(13430.6² +999.188²)/10.2 ≈ 1320.36 . . . m/s

3 0
3 years ago
A potential energy function is given by U(x)=(3.00J)x+(1.00J/m2)x3. What is the force function F(x) (in newtons) that is associa
Anit [1.1K]

Answer:

F(x)=-3 N - (3N)x^2

Explanation:

The force is defined as the negative of the derivative of the potential energy:

F=-\frac{dU}{dx}

If we use the potential energy function given in this problem:

U(x)=3.00 x + 1.00 x^3

and we calculate the force, we get:

F(x)=-\frac{d}{dx}(3x+x^3)=-3-3x^2

So, the force is

F(x)=-3 N - (3N)x^2

5 0
3 years ago
Read 2 more answers
A rocket is fired at 100 m/s at an angle of 37, what was its speed at the top of its path?
Nadusha1986 [10]

Answer:

0m/s

Explanation:

Since its fired at an angle, at the top there will be a split second where the velocity will be 0, as it has a parabolic shape, so the speed at the top of its path is 0

4 0
3 years ago
Can someone pls help me and give me the answers i will mark brainliest :3
Katyanochek1 [597]

Answer:

with what subject

Explanation:

i really only do ELA and sometimes science

8 0
3 years ago
The turnbuckle is tightened until the tension in the cable AB equals 2.3 kN. Determine the vector expression for the tension T a
brilliants [131]

Answer:

a) 0.83984 i + 0.41992 j - 2.0996 k KN

b) T_ac = 1.972888 KN

Explanation:

Given:

- The tension in cable AB = 2.3 KN

Find:

a) Determine the vector expression for the tension T as a force acting on member AD.

b) Also find the magnitude of the projection of T along the line AC.

Solution:

part a)

- Find unit vector AB:

                            vector (AB) = 2 i + j - 5 k

                             mag (AB) = sqrt (2^2 + 1^2 + 5^2)

                             mag (AB) = sqrt(30)

                             unit (AB) =  ( 1 / sqrt(30) )* ( 2 i + j - 5 k )

- Find Tension vector:

                             vector (T) = unit(AB)* 2.3 KN

                                              = 0.83984 i + 0.41992 j - 2.0996 k

- The projection of T onto AC can be found from the dot product of vector T to unit vector (AC)

- For unit vector (AC)

                               vector (AC) = 2 i - 2 j - 5 k

                               mag (AC) = sqrt (2^2 + 2^2 + 5^2)

                               mag (AC) = sqrt(33)

                               unit (AC) =  ( 1 / sqrt(33) )* ( 2 i - 2 j - 5 k )

- Compute the projection:

                                T_ac = vector T . unit (AC)

T_ac = (0.83984 i + 0.41992 j - 2.0996 k)  . ( 1 / sqrt(33) )* ( 2 i - 2 j - 5 k )

                                T_ac = 0.2923947572 - 0.146973786 - 1.827467232

                                T_ac = 1.972888 KN

4 0
3 years ago
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