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4 years ago

Why is the solar system considered a natural system

2 answers:

5 0

The Solar System Is A Natural System Because Humans Didn't Make It. They Didn't Put It There. Natural Is When Something Was There, That Humans Didn't Create, Didn't Put There, It Was A Natural Thing. Buildings Are Not Natural. We Made Buildings. They Are Man Made. The Sky, Is Natural. We Can Not Make The Sky.
~Spades15

statuscvo [17]4 years ago

3 0

The correct answer is :
It's a natural system so
it's controlled by natural forces
and i orbits by the sun
also humans aren't running it

You might be interested in

Two bodies A and B with 8 Kg and 24 kg respectively move

Contact [7]

It’s a speed of 15 m/s so it would be their velocities after collision

6 0

3 years ago

A driver slows down her car from 32.7 km/hr at a constant rate of 0.63 m/s2 just by taking her foot of the accelerator (the gas

prohojiy [21]

Answer: She moves 5.616 meters in that second.

Explanation:

If we define t = 0s as the moment when she starts decelerating we can write the function of acceleration as:

a(t) = -(0.63 m/s^2)

where the negative sign is because she is slowing down.

The velocity equation can be found if we integrate over time:

v(t) = -(0.63m/s^2)*t + v0

Where v0 is the constant of integration, that represents the initial velocity, in this case is:

v0 = 32.7 km/h

Now, because the acceleration is in m/s^2, we should write this velocity in m/s.

in one km we have 1000 meters, and in one hour we have 3600 seconds, then we have that:

32.7 km/h = 32.7 *(1000/3600) m/s = 9.08 m/s

Then the velocity equation becomes:

v(t) = -(0.63m/s^2)*t + 9.08 m/s

And for the position equation, we should integrate again to get:

p(t) = -(1/2)*(0.63m/s^2)*t^2 + (9.08m/s)*t + p0

Where p0 is the initial position.

For this problem, we want to find the distance that she moved between t = 5s and t = 6s, and that can be calculated as:

D = p(6s) - p(5s)

D = -(1/2)*(0.63m/s^2)*(6s)^2 + (9.08m/s)*6s + p0 +(1/2)*(0.63m/s^2)*(5s)^2 - (9.08m/s)*(5s) - p0

D = -(1/2)*(0.63m/s^2)*((6s)^2 - (5s)^2) + (9.08m/s)*(6s - 5s)

D = 5.615 m

She moves 5.616 meters in that second.

7 0

3 years ago

A 0.537-kg basketball is dropped out of a window that is 5.88 m above the ground. The ball is caught by a person whose hands are

Monica [59]

Answer:

a) 20.54 J

b) 30.97 J

c) 10.43 J

d) -20.54 J

Explanation:

m = Mass

g = Acceleration due to gravity = 9.81 m/s²

h = Height

$W=mgh\\\Rightarrow W=0.537\times 9.81\times (5.88-1.98)\\\Rightarrow W=0.537\times 9.81\times 3.9\\\Rightarrow W=20.54\ J$

Work done by the ball's weight is 20.54 J

$W=mgh\\\Rightarrow W=0.537\times 9.81\times (5.88)\\\Rightarrow W=30.97\ J$

Gravitational potential energy of the basketball, relative to the ground, when it is released is 30.97 J

$W=mgh\\\Rightarrow W=0.537\times 9.81\times (1.98)\\\Rightarrow W=10.43\ J$

Gravitational potential energy of the basketball, relative to the ground, when it is released is 10.43 J

Change in gravitational potential energy

$\Delta U=10.43-30.97=-20.54\ J$

Change in gravitational potential energy is given by -20.54 J

4 0

4 years ago

A stone is dropped into a river from a bridge 44.0 m above the water. Another stone is thrown vertically down 1.72 s after the f

Mariana [72]

Answer:

u₀ = 17.14 m/s

Explanation:

given,

bridge height = 44 m

initial speed of the first stone = 0 m/s

initial speed of the second stone = ?

difference after which the second stone is thrown = 1.72 s

for stone 1

$h = ut + \dfrac{1}{2}gt^2$

$h =\dfrac{1}{2}gt_1^2$

for stone 2

$h = u_0 (t_1-t) + \dfrac{1}{2}g (t_1-t) ^2$

$t_1 =\sqrt{\dfrac{1}{2}gh}$

$t_1 = \sqrt{\dfrac{1}{2}\times 9.81\times 44}$

t₁ = 14.69 s

$44 = u_0 \times 1.72 + \dfrac{1}{2}g\times 1.72 ^2$

u₀ = 17.14 m/s

8 0

4 years ago

When all the spheres on earth interact, that is known as _______

amm1812

Answer:

interactions?

maybe?

Explanation:

7 0

3 years ago