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mote1985 [20]
3 years ago
9

9. If you leave a paperclip stuck to a magnet long enough, the paperclip can become magnetic. Explain how this happens. Include

discussion of the “tiny magnet” property of atoms and domains.
Physics
1 answer:
Virty [35]3 years ago
4 0

Answer:

Each atom acts as a tiny magnet, when the magnetic field of each of the tiny magnets are aligned together, it gives a north pole and south pole. This is brought about due to prolonged exposure to a permanent magnet, which has caused the alignment of the atoms' individual magnetic fields to attain polarity. If the paperclip is made of iron, it can be magnetized and demagnetized easily. Once the paperclip is removed from the magnet, it will lose its magnetic properties.

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How do the structures of the respiratory system work together to supply my body with oxygen and get rid of carbon dioxide? do no
AlexFokin [52]

A

Explanation:

I hate tiny links OMLJDJDJDJSJDJJDJDJ

5 0
3 years ago
What event, which occurs twice a year when the sun crosses Earth's equator, recently
andrey2020 [161]

Answer:

<u>the autumnal equinox (when day and night are of equal length)</u>

<u>Explanation:</u>

The first event occurs around the 22nd or 23rd in the month of September. What usually happens is that regions around the Northern Hemisphere (which includes all of North America and Europe) experience an equal length of day and night.

While the second event occurs around March 20th or 21st mainly observable in countries found in the Southern Hemisphere.

5 0
3 years ago
If a ????=87.5 kgm=87.5 kg person were traveling at ????=0.900????v=0.900c , where ????c is the speed of light, what would be th
Diano4ka-milaya [45]

Answer:

\frac{K.E_r}{K.E}=2.875

Explanation:

Given:

mass, m = 87.5kg

Velocity, V = 0.900c

now,

the relativistic kinetic energy id given as:

K.E_r=(\gamma-1)mc^2 ...........(1)

where,

\gamma = relativistic factor, given as; \gamma=\frac{1}{\sqrt{1-\frac{v^2}{c^2}}}

Now, the classical kinetic energy is given as:

K.E = \frac{1}{2}mv^2    ..........(2)

Dividing the equation (1) by (2) we get

\frac{K.E_r}{K.E}=\frac{(\gamma-1)mc^2}{\frac{1}{2}mv^2}

or

\frac{K.E_r}{K.E}=\frac{(\gamma-1)c^2}{\frac{1}{2}v^2}

substituting the values in the equation we get,

\frac{K.E_r}{K.E}=\frac{(\frac{1}{\sqrt{1-\frac{(0.90c)^2}{c^2}}}-1)c^2}{\frac{1}{2}\times(0.90c)^2}

or

\frac{K.E_r}{K.E}=2.875

5 0
3 years ago
Paauto A: Isulat sa papel ang alpabetong Ingles at bilang I hanggang 10 sa istilong
sveta [45]

Answer:

Explanation:

English alphabets numbered fro 1 to 26

and the numbers 1 to10 so they are written in roman numbers as

1 - I

2 - II

3 - III

4 - IV

5 -V

6 - VI

7 -VII

8 - VIII

9 - IX

10 -X

11 - XI

12 - XII

13 - XIII

14 - XIV

15 - XV

16 - XVI

17 - XVII

18 - XVIII

19 - XIX

20- XX

21 - XXI

22 - XXII

23 - XXIII

24 - XXIV

25 - XXV

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8 0
3 years ago
19. Calculate the work done when a 30 N force pushes a rock 10 m. a) 3J b) 0.33 J c) 40 J d) 300 J
aksik [14]

19. Calculate the work done when a 30 N force pushes a rock 10 m. a) 3J b) 0.33 J c) 40 J d) 300 J

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25. A force of 100 newtons was necessary to lift a rock. A total of 150 joules of work was done. How far was the rock lifted? a) 1.5 m b) 15 m c) 0.15 m d) 150 m19. Calculate the work done when a 30 N force pushes a rock 10 m. a) 3J b) 0.33 J c) 40 J d) 300 J

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23. 45J of work were done on the object that moved 5M. How much force was applied to the object? a) 8N b) 9N c) 225N d) ON

24. If you do 40 joules of work lifting a 10N box, how high is the shelf you move it to. a) 400m b) 50m c) 40m d) 4m

25. A force of 100 newtons was necessary to lift a rock. A total of 150 joules of work was done. How far was the rock lifted? a) 1.5 m b) 15 m c) 0.15 m d) 150 m

<em><u>please</u></em><em><u> </u></em><em><u>mark</u></em><em><u> </u></em><em><u>me</u></em><em><u> </u></em><em><u>as</u></em><em><u> </u></em><em><u>brainliest</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

<em><u>follow</u></em><em><u> </u></em><em><u>me</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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