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2 years ago

A baseball is thrown at a speed of Vo at an angle of elevation θ. Determine its range (R) in terms of Vo and θ.

Physics

1 answer:

aksik [14]2 years ago

4 0

The range of baseball thrown at a speed of Vo at an angle of elevation theta is Vo^2sin2theta/g.

<h3>What is range and how it comes out to be so ?</h3>

See we have already studied about projectile in so many instances and in our earlier classes also.
Projectile is simply a thing or an object thrown at a speed by the means of external force under the influence of gravity.
Range is the maximum height that can be attained by the projectile , that is thrown up.
We can also sometimes depict it as the horizontal displacement of the projectile.
Whenever we throw a baseball up at sky , there is a launch point , the distance between the launch point and the end point is range.

To know more about range visit:

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A baseball is thrown at a speed of Vo at an angle of elevation θ. Determine its range (R) in terms of Vo and θ.​

A baseball is thrown at a speed of Vo at an angle of elevation θ. Determine its range (R) in terms of Vo and θ.