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EleoNora [17]
1 year ago
5

 A baseball is thrown at a speed of Vo at an angle of elevation θ. Determine its range (R) in terms of Vo and θ.​

Physics
1 answer:
aksik [14]1 year ago
4 0

The range of baseball thrown at a speed of Vo at an angle of elevation theta is Vo^2sin2theta/g.

<h3>What is range and how it comes out to be so ?</h3>
  1. See we have already studied about projectile in so many instances and in our earlier classes also.
  2. Projectile is simply a thing or an object thrown at a speed by the means of external force under the influence of gravity.
  3. Range is the maximum height that can be attained by the projectile , that is thrown up.
  4. We can also sometimes depict it as the horizontal displacement of the projectile.
  5. Whenever we throw a baseball up at sky , there is a launch point , the distance between the launch point and the end point is range.

To know more about range visit:

brainly.com/question/17016688

#SPJ13

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Which of the following concepts helps explain the modern technology used in 3D films?
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Answer:

a.

Explanation:

6 0
3 years ago
The greatest variation in size, mass, and luminosity occurs in:.
Sidana [21]

The greatest variation in size, mass, and luminosity occurs in elliptical galaxies.

<h3>What is Variation?</h3>

This is defined as the difference from the norm which is exhibited by objects.

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8 0
2 years ago
Compare the properties of Titan’s atmosphere with those of Earth’s atmosphere.
Aloiza [94]

Answer and Explanation:

Comparison between the Titan's atmosphere and earth atmosphere

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5 0
3 years ago
"5 N, up" is an example of a ___.<br> OA) force<br> OB) mass<br> OC) weight<br> OD) magnitude
Sunny_sXe [5.5K]

Answer:

A) Force

Explanation:

It is an example of force since force is a vector quantity so it has magnitude and direction. In this case the magnitude is equal to 5 [N] and the direction is upward.

The weight can not be, as it always acts downward.

Mass is not a force, its unit is given usually in kilogram [kg]

5 0
3 years ago
A ball is released from the top of a hill. How fast is the ball going when it reaches the base of the hill? Approximate g as 10
irina [24]
First I’ll show you this standard derivation using conservation of energy:
Pi=Kf,
mgh = 1/2 m v^2,
V = sqrt(2gh)
P is initial potential energy, K is final kinetic, m is mass of object, h is height from stopping point, v is final velocity.
In this case the height difference for the hill is 2-0.5=1.5 m. Thus the ball is moving at sqrt(2(10)(1.5))=
5.477 m/s.
5 0
2 years ago
Read 2 more answers
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