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EleoNora [17]
1 year ago
5

 A baseball is thrown at a speed of Vo at an angle of elevation θ. Determine its range (R) in terms of Vo and θ.​

Physics
1 answer:
aksik [14]1 year ago
4 0

The range of baseball thrown at a speed of Vo at an angle of elevation theta is Vo^2sin2theta/g.

<h3>What is range and how it comes out to be so ?</h3>
  1. See we have already studied about projectile in so many instances and in our earlier classes also.
  2. Projectile is simply a thing or an object thrown at a speed by the means of external force under the influence of gravity.
  3. Range is the maximum height that can be attained by the projectile , that is thrown up.
  4. We can also sometimes depict it as the horizontal displacement of the projectile.
  5. Whenever we throw a baseball up at sky , there is a launch point , the distance between the launch point and the end point is range.

To know more about range visit:

brainly.com/question/17016688

#SPJ13

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1200

Explanation:

F = m x (v / t)

v / t = F / m

v = (F / m) / t

v = (600 / 5) / 0.1

v = 120 / 0.1

v = 1200 m / s

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When an object is placed 30.0 cm in front of a concave mirror, a real image is formed 60.0 cm
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f = o * i / (o + i) = 60 * 30 / (60 + 30) = 1800 / 90 = 20 cm

Both the object and image are in positive space for a mirror

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4 years ago
Unas niñas en el receso estaban jugando a derramar flatulencias en un frasco de forma cilíndrica, cuyo radio tenía 5" y una altu
hram777 [196]

Answer:

Los gases siempre se adaptaran al volumen del contenedor en el que estén.

Entonces, si baja la presión del gas, la temperatura se mantendrá constante, lo que implica que tiene que aumentar la temperatura, pues para un gas ideal tenemos:

P*V = n*k*T

donde si el frasco esta cerrado, tenemos que n, k y V son constantes, entonces:

P = (n*k/V)*T

P = constante*T

(Notar que si el frasco no estuviera cerrado, entonces el numero n variaría de forma incontrolable, y este problema no se podría resolver de forma sencilla)

Entonces, si la presión baja, también baja la temperatura, pero el volumen se mantendrá constante, eso es lo importante.

Como el volumen se mantiene constante, el volumen que tomara el gas va a ser igual al volumen del frasco, sabemos que el volumen de un cilindro es:

V = (pi*r^2*h)

donde:

r = radio

pi = 3.14

h = altura.

en este caso, r = 5'' = 5 in

                       h = 7 in

Entonces el volumen sera:

V = 3.14*(5in)^2*7in = 549.5 in^2

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