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Iteru [2.4K]
3 years ago
11

Suppose that the Hubble Space Telescope discovers a series of planets with the following characteristics moving around a star th

at resembles our Sun: spherical, solid surfaces; mean densities about four times that of water; radii about 4000 km; low-density atmospheres. How would these planets be classified in comparison with our solar system?A. Jovian planets B. cometary nuclei C. asteroids D. terrestrial planetsE. comets
Physics
1 answer:
nalin [4]3 years ago
3 0

Answer:

Option (D)

Explanation:

Terrestrial planets refers to those four planets that are nearest to the sun and that lies within the asteroid belt. These planets are mainly composed of rocks or other metal objects that have a hard and resistant surface on it. They have a metal core that is molten (liquid) in nature, and atmosphere is relatively less dense, and also various geological features are present on it like the crater, volcanoes which can be observed with the help of satellites. The average densities of these planets is about four times the density of water. For example, the density of water is 1 g/cm³, whereas the density of earth is 5.5 g/cm³.

Thus, the correct answer is option (D).

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What's the average speed of an object moving 3790 meters in 249 s.
NISA [10]

Heya!!

For calculate velocity, lets applicate formula

                                                 \boxed{d = v * t}

                                               <u>Δ   Being   Δ</u>

                                         d = Distance = 3790 m

                                             t = Time = 249 s

                                             v = Velocity = ?

⇒ Let's replace according the formula and clear "v":

\boxed{v= 3790\ m / 249\ s}

⇒ Resolving

\boxed{ v = 15,22 \ m/s }

Result:

The velocity is <u>15,22 meters per second.</u>

Good Luck!!

4 0
3 years ago
What is the length x of the side of the triangle below? (Hint: use the cosine function.)
Firlakuza [10]
A because that is the answer
7 0
3 years ago
A child is holding a wagon from rolling straight back down in a driveway that inclined at 20 degree horizontal. if the wagon wei
Alenkinab [10]

Answer:

F = 51.3°

Explanation:

The component of weight parallel to the inclined plane must be responsible for the rolling back motion of the car. Hence, the force required to be applied by the child must also be equal to that component of weight:

F = Parallel\ Component\ of\ Weight\ of\ Wagon= WSin\theta\\

where,

W = Weight of Wagon = 150 N

θ = Angle of Inclinition = 20°

Therefore,

F = (150\ N)Sin\ 20^o

<u>F = 51.3°</u>

8 0
3 years ago
What is the volume of a rock with a density of 3.00 g/cm3 and a mass of 600g?
Mademuasel [1]
The equation of D = m/V

Where D = density
m = mass
and V = volume

We are solving for V, so with the manipulation of variables we multiply V on both sides giving us 
V(D) = m 
now we divide D on both sides giving us
V = m/D 

We know our mass which is 600g and our density is 3.00 g/cm^3
so
V = 600g/3.00g/cm^3 = 200cm^3  or 200mL

a cubic centimeter (cm^3) is one of the units for volume. It's exactly like mL. 1 cm^3 = 1 mL
 
If you wish to change it to L, you'd have to convert. 
5 0
3 years ago
Anyone know what type of circuit this is?
Oksana_A [137]

Answer:

C

Explanation:

BECAUSE ITS GOING ON AND ON IF ITS NOT CORRECT I WILL VOTE YOU BRAINLEST ON MY QUESTION

3 0
3 years ago
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