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ArbitrLikvidat [17]
3 years ago
5

The resistance of a wire depends on

Physics
1 answer:
Orlov [11]3 years ago
6 0

Answer:

b

Explanation:

because all are factors that determine the resistivity of a material

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you stand on a straight desert road at night and observe a vehicle approaching. this vehicle is equipped with two small headligh
inysia [295]

Answer:

The distance that you marginally able to discern that there are two headlights rather than a single light source is 6.084 km

Explanation:

Given:

d = distance = 0.679 m

λ = wavelength of the light = 537 nm = 537x10⁻⁹m

dp = pupil diameter = 4.81 mm = 0.00481 m

Question: What distance, in kilometers, are you marginally able to discern that there are two headlights rather than a single light source, dx = ?

For the separation of the peak from the central maximum it is:

sin\theta =\frac{\lambda }{d_{p} } =\frac{537x10^{-9} }{0.00481} =1.116x10^{-4}

In this case, the two small sources of the headlights have the same angle as the images that form inside the eye

d_{x} =\frac{d}{sin\theta } =\frac{0.679}{1.116x10^{-4} } =6.084x10^{3} m=6.084km

7 0
3 years ago
Capacitors in Combination: A 5.0-μF, a 14-μF, and a 21-μF capacitor are connected in series. How much capacitance would a single
tankabanditka [31]

The total capacitance is <em>C</em> such that

1/<em>C</em> = 1/(5.0 µF) + 1/(14 µF) + 1/(21 µF)

Solve for <em>C</em> :

<em>C</em> = 1 / (1/(5.0 µF) + 1/(14 µF) + 1/(21 µF)) ≈ 3.1 µF

7 0
3 years ago
What is an essential characteristic of an object in equilibrium
Alecsey [184]

Answer:

The essential characteristics of an object in equilibrium is acceleration of the object must  be zero.

Explanation:

Equilibrium: An object acted upon by several forces is said to be in equilibrium if it does no it moves or rotate. Equilibrium can be defined as the state of stability of an object.

Condition for equilibrium

(i) The resultant force acting on the object must me equal to zero.

(ii) The sum of moment acting on the object must be equal to zero.

But.

F = ma..................... Equation 1

Where F =  net force , m = mass, a = acceleration.

from the equation above,

For  F = 0 N, a must be equal to zero.

<em>From the above, the essential characteristics of an object in equilibrium is acceleration must be zero</em>

6 0
3 years ago
Explain how mass and distance affect gravity (and other non-contact forces for that matter)
Anestetic [448]

Answer:

How Do Mass and Distance Affect the Force of Gravity Between Two Objects?  

The force of gravity between two objects is determined by the mass of each object and the distance between their centers. Objects with a greater amount of mass will exert a greater degree of gravitational pull, but as the distance between two objects increases, the gravitational force between them lessens.

Explanation:

An example of the significance of distance in Newton's law is how a person's weight decreases when they are further away from the center of the Earth, such as in an orbiting space station. The gravitational force, experienced as weight, is decreased, even through the person's mass and that of the Earth remain the same.

4 0
2 years ago
Chapter 38, Problem 001
Norma-Jean [14]

Answer:

a) \lambda=2.95x10^{-6}m

b) infrared region

Explanation:

Photon energy is the "energy carried by a single photon. This amount of energy is directly proportional to the photon's electromagnetic frequency and is inversely proportional to the wavelength. If we have higher the photon's frequency then we have higher its energy. Equivalently, with longer the photon's wavelength, we have lower energy".

Part a

Is provide that the smallest amount of energy that is needed to dissociate a molecule of a material on this case 0.42eV. We know that the energy of the photon is equal to:

E=hf

Where h is the Planck's Constant. By the other hand the know that c=f\lambda and if we solve for f we have:

f=\frac{c}{\lambda}

If we replace the last equation into the E formula we got:

E=h\frac{c}{\lambda}

And if we solve for \lambda we got:

\lambda =\frac{hc}{E}

Using the value of the constant h=4.136x10^{-15} eVs we have this:

\lambda=\frac{4.136x10^{15}eVs (3x10^8 \frac{m}{s})}{0.42eV}=2.95x10^{-6}m

\lambda=2.95x10^{-6}m

Part b

If we see the figure attached, with the red arrow, the value for the wavelenght obtained from part a) is on the infrared region, since is in the order of 10^{-6}m

4 0
3 years ago
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