I have found this variation on the ideal gas equation to be very handy.
PV = nRT ..... n = m / M.... where m is mass, M is molar mass
PV = mRT / M
m = PVM / RT
m = 1.75 atm x 3.00L x 28.0g/mol / 0.0821 Latm/molK / 295K
m = 6.07g
The grams of ammonia are in the flash is a total of 6.07 grams
Answer:
234 KJ ≡ 55.887 Kcal
Explanation:
∴ J ≡ Kg/m².s² ≡ N.m = 0.2389 cal
∴ cal = 4.187 J
⇒ 234 KJ * ( 1000 J / KJ ) * ( cal / 4.187 J ) * ( Kcal / 1000 cal ) = 55.887 Kcal
the answer is B because I jus did that
Answer:
0.0933 moles/Litre
Explanation:
We assume that the number of moles of N- used is equal to the number of moles of Nitrogen containing compounds that are generated due to the fact that the nitrogen containing compound that are produced contain only one nitrogen in each atom. As such, finding the amount of nitrogen used up explains the amount of compound formed. This can be expressed as follows:
Energy cost =
Given that:
Energy = 100 W for 60 minutes
100 W = 100 J/s
= 100 J/s × (60 × 60) seconds
= 3.6 × 10⁵ J
Let now convert 3.6 × 10⁵ J to eV; we have:
= ( 3.6 × 10⁵ × 6.242 × 10¹⁸ )eV
= 2.247 × 10²⁴ eV
So, number of N-atom used up to form compounds will now be:
= 2.247 × 10²⁴ eV ×
= 1.123 × 10²³ N-atom
To moles; we have:
=
= 0.186 moles
However, we are expected to leave our answer in concentration (i.e in moles/L)
since we are given 2L
So; 0.186 moles ⇒
= 0.0933 moles/Litre
Answer:
Os óxidos são compostos binários formados pela reação do oxigênio com outros elementos. O oxigênio é altamente reativo por natureza. Eles reagem com metais e não metais para formar óxidos.
Os óxidos normalmente reagem com ácidos ou bases, às vezes ambos. ... Os metais tendem a formar óxidos básicos, os não metais tendem a formar óxidos ácidos e os óxidos anfotéricos são formados por elementos próximos à fronteira entre metais e não metais (metaloides).
Explanation: