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Yanka [14]
2 years ago
12

The density of seawater is 1.025 g/ml what is the mass of 100,000 ml of seawater in grams

Chemistry
1 answer:
melamori03 [73]2 years ago
8 0
D = m / V

1.025 = m / 100,000 mL

m = 1.025 x 100,000

m = 102,500 g
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2. How many grams of zinc will be formed if 32.0 g of copper reacts with zinc nitrate? Copper(I)nitrate is the other product.
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16.46 g.

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<em>2Cu + Zn(NO₃)₂ → Zn + 2Cu(NO₃).</em>

  • It is clear that 2.0 moles of Cu reacts with 1.0 mole of Zn(NO₃)₂ to produce 1.0 mole of Zn and 2.0 moles of Cu(NO₃).
  • We need to calculate the number of moles of the reacted Cu (32.0 g) using the relation:

<em>n = mass / molar mass</em>

  • The no. of moles of Cu = mass / atomic mass = (32.0 g) / (63.546 g/mol) = 0.503 mol.

<u><em>Using cross multiplication:</em></u>

2.0 moles of Cu produces → 1.0 mole of Zn, from the stichiometry.

0.503 mole of Cu produces → ??? mole of Zn.

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3 0
3 years ago
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