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Paha777 [63]
3 years ago
6

The tarnish that forms on objects made of silver is solid silver sulphide. This can be removed by reacting it with aluminium met

al to produce silver metal and solid aluminium sulphide. How many moles of the excess reactant remain unreacted after the reaction between 3.4 moles of silver sulphide with 8.1 moles of aluminium metal is finished?
Chemistry
1 answer:
steposvetlana [31]3 years ago
6 0

Answer:

5.83 mol.

Explanation:

  • From the balanced reaction:

<em>2Al + 3Ag₂S → 6Ag + Al₂S₃,</em>

It is clear that 2 mol of Al react with 3 mol of Ag₂S to produce 1 mol of Ag and 1 mol of Al₂S₃.

Al reacts with Ag₂S with (2: 3) molar ratio.

<em>So, 2.27 mol of Al reacts completely with 3.4 mol of Ag₂S with (2: 3) molar ratio.</em>

<em />

  • The limiting reactant is Ag₂S.
  • The excess "left over" reactant is Al.

The reamining moles of excess reactant "Al" = 8.1 mol - 2.27 mol = 5.83 mol.

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The point at which one drop of base turns the acid indicator into a pink color that lasts for thirty seconds in doing titration is called the end point or the equivalence point.

End point or the equivalence point is the one responsible for the pink color that lasts for thirty seconds.
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3 years ago
Rock and ice particles make up the ____ of the Jovian planets? Ring system, craters, volcanoes, or asteroids
lara31 [8.8K]
Jovian planets are what we call the "gas giants," so immediately we can eliminate craters or volcanos because they don't have a solid surface. asteroids in space doesn't belong to any specific planet, so the answer is ring systems.
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3 years ago
An atom X has 2 electrons in its outer orbit. What will it do to form a stable ion?
matrenka [14]

Answer:

In a neutral molecule, the sum of the bonding valance electrons must be equal. So the products of the negative element and its charges and the positive element and its charge must be equal.

Explanation:

C1×N1 = C2×N2

If we have a 3 valance electrons , the 'A' charge will be either +3 or -5 for a full octet and valance electron in 'B' atoms will mostly result in acquisition of additional electrons (2) for an octet and relative charge of -2.

Balancing the two,

3 × A = -2 × B

To be equal, A = 2 and B = 3

Therefore, A²B³

6 0
2 years ago
A solution is made by dissolving 23.5 grams of glucose (C6H12O6) in 0.245 kilograms of water. If the molal freezing point consta
aalyn [17]

Answer:

- 0.99 °C ≅ - 1.0 °C.

Explanation:

  • We can solve this problem using the relation:

<em>ΔTf = (Kf)(m),</em>

where, ΔTf is the depression in the freezing point.

Kf is the molal freezing point depression constant of water = -1.86 °C/m,

m is the molality of the solution (m = moles of solute / kg of solvent = (23.5 g / 180.156 g/mol)/(0.245 kg) = 0.53 m.

<em>∴ ΔTf = (Kf)(m)</em> = (-1.86 °C/m)(0.53 m) =<em> - 0.99 °C ≅ - 1.0 °C.</em>

4 0
3 years ago
ethanol is a common laboratory solvent and has a density of 0.789 g/mL. what is the mass, in grams, of 151 mL of ethanol
natta225 [31]
<em>V = 151 mL = 151 cm³</em>
<em>d = 0,789 g/mL = 0,789 g/cm³</em>
--------------------------------------

d = m/V
m = d×V
m = 0,789×151
<u>m = 119,139g</u>

3 0
3 years ago
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