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Paha777 [63]
3 years ago
6

The tarnish that forms on objects made of silver is solid silver sulphide. This can be removed by reacting it with aluminium met

al to produce silver metal and solid aluminium sulphide. How many moles of the excess reactant remain unreacted after the reaction between 3.4 moles of silver sulphide with 8.1 moles of aluminium metal is finished?
Chemistry
1 answer:
steposvetlana [31]3 years ago
6 0

Answer:

5.83 mol.

Explanation:

  • From the balanced reaction:

<em>2Al + 3Ag₂S → 6Ag + Al₂S₃,</em>

It is clear that 2 mol of Al react with 3 mol of Ag₂S to produce 1 mol of Ag and 1 mol of Al₂S₃.

Al reacts with Ag₂S with (2: 3) molar ratio.

<em>So, 2.27 mol of Al reacts completely with 3.4 mol of Ag₂S with (2: 3) molar ratio.</em>

<em />

  • The limiting reactant is Ag₂S.
  • The excess "left over" reactant is Al.

The reamining moles of excess reactant "Al" = 8.1 mol - 2.27 mol = 5.83 mol.

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According to the following reaction, what volume in milliliters of 0.244M KCl(aq) solution is required to react exactly with 50.
Elodia [21]

Answer:

There is 86.1 mL of KCl needed

Explanation:

<u>Step 1:</u> Data given

Molarity of KCl = 0.244 M

Volume of a 0.210 M Pb(NO3)2 = 50.0 mL = 0.05 L

<u>Step 2:</u> The balanced equation

2KCl(aq) + Pb(NO3)2(aq) -> PbCl2(s) + 2KNO3(aq)

<u>Step 3:</u> Calculate moles Pb(NO3)2

moles Pb(NO3)2 =molarity * volume

moles Pb(NO3)2 = 0.210 M * 0.05 L

moles Pb(NO3)2 = 0.0105 moles

<u>Step 4:</u> Calculate moles of KCl

For 1 mole of Pb(NO3)2 we need 2 moles of KCl

moles KCl required = 0.0105 * 2 =0.0210  moles

<u>Step 5:</u> Calculate volume of KCl

Volume = moles KCl / molarity KCl

V = 0.0210 moles / 0.244 M=0.0861 L = 86.1 mL

There is 86.1 mL of KCl needed

6 0
3 years ago
What elements on the periidic table are metalloids<br><br>​
butalik [34]

Answer:

Boron (B)

Silicon (Si)

Germanium (Ge)

Arsenic (As)

Antimony (Sb)

Tellurium (Te)

Polonium (Po)

8 0
3 years ago
The permanent electric dipole moment of the water molecule 1H2O2 is 6.2 * 10-30 C m. What is the maximum possible torque on a wa
stellarik [79]

Answer:

3.1 x 10⁻²¹ Nm

Explanation:  

When placed in an external electric filed, an electric dipole experiences a torque. and this torque is represented mathematically with the equation:

torque (τ) = dipole moment vector (P) x electric field vector (E)

τ = P. E . sin θ

where θ is the angle between the water molecule and the electric field, which in this case is 90° (because this is where the torque is maximum)

τ = 6.2x10⁻³⁰Cm . 5.0x10⁸ N/C . sin90

τ = 6.2x10⁻³⁰Cm . 5.0x10⁸ N/C . 1

solve for τ

τ = 3.1 x 10⁻²¹ Nm

the maximum possible torque on the water molecule is therefore 3.1 x 10⁻²¹ Nm

7 0
3 years ago
Using water to measure the volume of small irregular shaped objects is called? *
Fed [463]

Answer:

B. water displacement is used "graduated cylinder is filled with water (100 mL) and the object is then put inside. ... If the new water level is (120 mL) we now know that the object has a volume of 20 mL."

Explanation:

4 0
2 years ago
Read 2 more answers
) determine the henry's law constant for ammonia in water at 25°c if an ammonia pressure of 0.022 atm produces a solution with a
Nataly [62]

Answer:

a. 59 m/atm

Explanation:

  • To solve this problem, we must mention Henry's law.
  • <em>Henry's law states that at a constant temperature, the amount of a given gas dissolved in a given type and volume of liquid is directly proportional to the partial pressure of that gas in equilibrium with that liquid.</em>
  • It can be expressed as: C = KP,

C is the concentration of the solution (C = 1.3 M).

P is the partial pressure of the gas above the solution (P = 0.022 atm).

K is the Henry's law constant (K = ??? M/atm),

∵ C = KP.

∴ K = C/P = (1.3 M)/(0.022 atm) = 59.0 M/atm.

3 0
3 years ago
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