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irina1246 [14]
3 years ago
13

Put this equation into function notation: y=(1200-2x)/3

Mathematics
1 answer:
Arte-miy333 [17]3 years ago
6 0
Y=mx+b
y=(1200-2x)/3
y=1200/3-2/3x
y=400-2/3x
y=-2/3x+400
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The school track has eight lanes. Each lane is 1.25 meters wide. The arc at each end of the track is 180. The distance of the ho
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Answer:

Part one: r5 = 41.5 m , r6 = 42.75 m , r7 = 44 m , r8 = 45.25  

Part two: Max ran 399.34 m in lane one

Part three: The distance in lanes 3 and 7 are 415.04 m and 446.46 m

Part four: Max ran in the three laps 1260.84 m around the track

Step-by-step explanation:

* lets explain how to solve the problem

- The school track has eight lanes

- Each lane is 1.25 meters wide

- The arc at each end of the track is 180° , that means the arc at each

 end is a semi-circle

- The distance of the home straight for all lanes is 85 m

- The radius of the first lane is 36.5 m

∵ The width of each lane is 1.25

∴ The radius of the second lane = 36.5 + 1.25 = 37.75

- That means the radius of each lane increased by 1.25 then the

  previous lane

∴ The radius of each lane = the radius of the previous lane + 1.25

# Part one:

∵ The radius of the 4 lane is 40.25

∴ The radius of the 5th lane = 40.25 + 1.25 = 41.5 m

∴ The radius of the  6th lane = 41.5 + 1.25 = 42.75 m

∴ The radius of the  7th lane = 42.75 + 1.25 = 44 m

∴ The radius of the  8th lane = 44 + 1.25 = 45.25 m

* r5 = 41.5 m , r6 = 42.75 m , r7 = 44 m , r8 = 45.25  

- The length of each lane is the lengths of the 2 end arcs and  2

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∵ The arc is a semi-circle

∵ The length of the semi-circle is πr

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∵ The length of the home straight distance is 85 m

∴ The length of each lane = 2πr + 2 × 85

∴ The length of each lane = 2πr + 170

# Part two:

- Max ran around lane one

∵ The radius of lane one = 36.5 m

∵ The distance of each lane = 2πr + 170

∴ The distance of lane one = 2π(36.5) + 170 = 399.34 m

* Max ran 399.34 m in lane one

# Part three:

- We will chose lanes 3 and 7

∵ The distance of each lane = 2πr + 170

∵ The radius of lane 3 = 39

∵ The radius of lane 7 is 44

∴ The distance of lane 3 = 2π(39) + 170 = 415.04 m

∴ The distance of lane 7 = 2π(44) + 170 = 446.46 m

* The distance in lanes 3 and 7 are 415.04 m and 446.46 m

# Part four:

- To find the total distance that Max ran in the 3 laps ad the answers

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∵ Max ran 399.34 m in lane one

∵ Max ran 415.04 m in lane three

∵ Max ran 446.46 m in lane seven

∴ The total distance of the 3 lanes = 399.34 + 415.04 + 446.46

∴ The total distance of the 3 lanes = 1260.84

* Max ran in the three laps 1260.84 m around the track

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Answer:

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Step-by-step explanation:

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