where M1 is the concentration of the stock solution, V1 is the volume of the stock solution, M2 is the concentration of the new solution and V2 is its volume.
6.00 M ( 1.0 L ) = ( 0.500 M ) V2
V2 = 12 L
Therefore, approximately 11 L of water should be added to the 1 L of 6.00 M solution. Hope this answers the question. Have a nice day.
Another M1V1=M2V2 <span>V1=1.0L </span> <span>M1=6.00M </span> <span>M2=0.500M </span> <span>V2=?? </span> <span>(6.00M)(1.0L)=(0.500M)V2 </span> <span>Solve for V2 you get 12L or 12000mL </span>
The element can also be called gold-197. It has Mass number
is 197, atomic number is 79 and electrons 79, Atoms that have the same number
of protons but different number of neutrons. Isotopes have identical numbers of
protons and electrons.
one mole of atom of any element contains6.022×1033 atoms regardless of the type of elements the mass of one mole of an element depend on what that element is and is equal to atom mass of that element in gram
