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3 years ago

Please what does this equal pleas help

Mathematics

2 answers:

Solnce55 [7]3 years ago

8 0

The answer is 24 because pemdas

aleksandrvk [35]3 years ago

6 0

14 using bedmas. Multiple then add the values to get this answer.

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Anna divided a sheet of paper into 5 equal sections in color 3 of the sections blue what percent of the paper did she color

e-lub [12.9K]

60/100 is 3/5 so Anna colored 60% of the paper blue

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3 years ago

To solve 9x²-12x+4=49 by using the square root property, you would first rewrite the equation as...

n200080 [17]

Answer:

Step-by-step explanation:

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3 years ago

Which point is on the circle centered at the origin with a radius of 5 units? Distance formula: StartRoot (x 2 minus x 1) square

Sergeeva-Olga [200]

Answer:

Option A) $(2,\sqrt{21})$

Step-by-step explanation:

The following information is missing in the question:

A. $(2,\sqrt{21})$

B. $(2,\sqrt{23})$

C. (2, 1)

D. (2, 3)

We are given the following in the question:

A circle centered at origin and radius 5 units.

We have to find the equation of a point that lies on the circle.

Let (x,y) lie on the circle.

Distance formula:

$d = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

Putting

$(x_2,y_2) = (x,y)\\(x_1.y_1) = (0,0)\\d = 5$

We get,

$5 = \sqrt{(y-0)^2 + (x-0)^2}\\\sqrt{x^2+y^2}=5\\x^2+y^2 = 25$

is the required equation of point on the circle centered at the origin with a radius of 5 units.

The point $(2,\sqrt{21})$ satisfies the given equation.

Verification:

$(2)^2 + (\sqrt{21})^2\\=4 + 21\\=25$

Thus, $(2,\sqrt{21})$ lies on the circle centered at the origin with a radius of 5 units.

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4 years ago

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Answer:46

Step-by-step explanation:

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