Answer:
ooouuhhggg
Step-by-step explanation:
iiiiijhhhjjjhhjjjnnnnnnjjj
600km??? Because it’s travelling 600km and hour so it’s average is 600km and hour
Answer:
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
Step-by-step explanation:
Given that;
the frequencies of there alternatives are;
Frequency A = 60
Frequency B = 12
Frequency C = 48
Total = 60 + 12 + 48 = 120
Now to determine our relative frequency, we divide each frequency by the total sum of the given frequencies;
Relative Frequency A = Frequency A / total = 60 / 120 = 0.5
Relative Frequency B = Frequency B / total = 12 / 120 = 0.1
Relative Frequency C = Frequency C / total = 48 / 120 = 0.4
therefore;
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
The answer for this would be 0.167
The correct option is B): "<span>Let x = 1st integer. Let x + 2 = 2nd integer.</span><span>"
Given that "The sum of two consecutive odd integers is 28."
Now the difference between two odd numbers is 2.
So this means that one odd number has to be greater than the other by 2.
Let the smaller number be 'X' therefore the bigger number will be 'x+2'
thus
x + (x+2) = 28
therefore,
x + x + 2 = 28
now we subtract "2" from both the sides
therefore,
2x = 26
now dividing throughout by 2 we get:
x = 13
therefore,
x + 2 = 13+2
= 15
therefore, the numbers are
13 AND 15</span>
