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Murljashka [212]
3 years ago
10

Each child at a birthday party was given $5 to spend at the arcade on games and rides. Each game costs $0.25 and each ride costs

$0.50. Write and graph an inequality for the number of games and rides a child can enjoy for $5. Is it possible for a child to play 12 games and go on 6 rides?
Mathematics
1 answer:
Dmitrij [34]3 years ago
7 0
No it is not possible to play 12 games and go on 6 rides
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What is y – 3 = 7 (x – 5) in standard form?
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Answer:

38=7x-y

Step-by-step explanation:

standard form= Ax+By+C

(y-3=7(x-5))

(y-3=7x-35)+3 to both sides

(y=7x-38) +38 to both sides

(y+38=7x) -y to both sides

38=7x-y

you have to move the 38 and y because if you moved the x value, than A becomes negative and it can't be in standard form

8 0
3 years ago
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Which statement is true about this equation? y=2x+4
alukav5142 [94]

Answer:

Answer and Explanation:

In solving y = 2x - 4, we find that the slope of the line is 2, the y-intercept of the line is y = -4, and the x-intercept of the line is x = 2.

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3 years ago
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The weights of college football players are normally distributed with a mean of 200 pounds and a standard deviation of 50 pounds
Feliz [49]

Answer:

0.3811 = 38.11% probability that he weighs between 170 and 220 pounds.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 200, \sigma = 50

Find the probability that he weighs between 170 and 220 pounds.

This is the pvalue of Z when X = 220 subtracted by the pvalue of Z when X = 170.

X = 220

Z = \frac{X - \mu}{\sigma}

Z = \frac{220 - 200}{50}

Z = 0.4

Z = 0.4 has a pvalue of 0.6554

X = 170

Z = \frac{X - \mu}{\sigma}

Z = \frac{170 - 200}{50}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743

0.6554 - 0.2743 = 0.3811

0.3811 = 38.11% probability that he weighs between 170 and 220 pounds.

6 0
3 years ago
Given that the expression 2x² -2.9x-3.6 can be factorized into the form 0.1(px+q)(rx+s), where p, q, r and s are integers, find
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~~2x^2-2.9x-3.6\\\\=\dfrac{20}{10}x^2 - \dfrac{29}{10} x-\dfrac{36}{10}  \\\\=\dfrac 1{10} (20x^2 -29x -361)\\\\=0.1(20x^2-29x-36)\\\\=0.1(20x^2-45x+16x-36)\\\\=0.1[5x(4x-9)+4(4x-9)]\\\\=0.1(5x+4)(4x-9)\\\\\text{Where,}~ p=5, ~ q=4,~ r=4~,s=-9\\\\\text{Hence,}~ \\\\p+q+r+s \\\\ = 5+4+4 -9 \\\\=13-9 \\\\ =4

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2 years ago
Holaa cómo están<br><br><br>espero que bien​
9966 [12]

Answer:

si muy bien y tu?

Step-by-step explanation:

6 0
3 years ago
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