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juin [17]
3 years ago
13

what is sum 18+57_

9%5Cend%7Barray%7D%5Cright%5D" id="TexFormula1" title="\left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]" alt="\left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
REY [17]3 years ago
7 0

Answer:

18+57= 75

Step-by-step explanation:

Next time use a calculator chuckle nuts

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(01.02 LC) Simplify 8 - (14)
nignag [31]

Answer:

8-14 or -6

Step-by-step explanation:


7 0
3 years ago
Entertainment Software Association would like to test if the average age of "gamers" (those that routinely play video games) is
lions [1.4K]

Answer:

"30 years or less when, in reality, the average age is more than 30 years"

Step-by-step explanation:

Type I error is produced when conclusion rejects a true null hypothesis.

The null hypothesis is

"The average gamer is more than 30 years old"

(deduced from the wording, not explicitly stated).

Then if the conclusion is "the average gamer is less than or equal to 30 years old" when in reality the average age is more than 30 years, then there is a type I error, since the null hypothesis is rejected.

Answer is D:

"30 years or less when, in reality, the average age is more than 30 years"

8 0
3 years ago
The ones circled please put the answers and what the problem is ok? and thank y'all for the support
Lady_Fox [76]
7) 2-3=-1         9) 6-9=-3
11) -3-4=-7      13) -7-6=-13
15)-3-9=-12     17) 6-(-2)=8
19)3-(-5)=8      21) 5-(-8)=13
23)-2-(-1)=-1   25) -10-(-4)=-6
27)-6-(-5)=-1   29) -8-(-6)=-2
31)5-(-3)=8      33) 7-10=-3
35)-2-5=-7       37) -9-(-4)=-5
5 0
3 years ago
If a manufacturer conducted a survey among randomly selected target market households and wanted to be 95​% confident that the d
katen-ka-za [31]

Answer:

We need a sample size of least 119

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Sample size needed

At least n, in which n is found when M = 0.09

We don't know the proportion, so we use \pi = 0.5, which is when we would need the largest sample size.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.09 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.09\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.09}

(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.09})^{2}

n = 118.6

Rounding up

We need a sample size of least 119

6 0
3 years ago
The product of 5 and a number, decreased by 9, is 306. What is the number?
steposvetlana [31]

Step-by-step explanation:

bsbdjdkksnsbsvsvns NC Ricans Roxane Isiah

5 0
3 years ago
Read 2 more answers
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