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<u>Answer:</u> The freezing point of solution is -3.34°C
<u>Explanation:</u>
Vant hoff factor for ionic solute is the number of ions that are present in a solution. The equation for the ionization of calcium nitrate follows:
The total number of ions present in the solution are 3.
- To calculate the molality of solution, we use the equation:
Where,
= Given mass of solute
= 11.3 g
= Molar mass of solute
= 164 g/mol
= Mass of solvent (water) = 115 g
Putting values in above equation, we get:
- To calculate the depression in freezing point, we use the equation:
where,
i = Vant hoff factor = 3
= molal freezing point depression constant = 1.86°C/m.g
m = molality of solution = 0.599 m
Putting values in above equation, we get:
Depression in freezing point is defined as the difference in the freezing point of water and freezing point of solution.
= 3.34 °C
Freezing point of water = 0°C
Freezing point of solution = ?
Putting values in above equation, we get:
Hence, the freezing point of solution is -3.34°C
This question is incomplete, the complete question is;
Now we will examine the electric field of a dipole. The magnitude and direction of the electric field depends on the distance and the direction. We will investigate in detail just two directions. With charges available in the simulation (all the charges are either positive or negative 1 nC increments).
how do you create a dipole with dipole moment 1 x 10-9 Cm with a direction for the dipole moment pointing to the right. Make a table below that shows the amounts of charge and the distance between the charges. There are many correct answers
Answer:
Given the data in question;
Dipole moment P = 1 × 10⁻⁹ C.m
now dipole pointing to the right;
P→
(-) ---------------->(+)
d
so let distance between the dipoles be d
∴ P = d
Let = 1 nC
so
P = d
1 × 10⁻⁹ = 1 × 10⁻⁹ × d
d = (1 × 10⁻⁹) / (1 × 10⁻⁹)
d = 1 m
Also Let = 2 nC
so
P = d
1 × 10⁻⁹ = 2 × 10⁻⁹ × d
d = (1 × 10⁻⁹) / (2 × 10⁻⁹)
d = 0.5 m
Also Let = 3 nC
so
P = d
1 × 10⁻⁹ = 3 × 10⁻⁹ × d
d = (1 × 10⁻⁹) / (3 × 10⁻⁹)
d = 0.33 m
such that;
charge distance
1 nC 1.00 m
2 nC 0.50 m
3 nc 0.33 m
4 nC 0.25 m
5 nC 0.20 m