Answer:
voltage and zero
Explanation:
I don't know i just did the Edg question
Answer:
R=0.5B+0.5C+2A+D
Explanation:
By the triangular law of vector addition
vector R= vector B- vector D
As A,B,C,D are edges of the parallelogram,
A is parallel to D but opposite in direction.
Therefore
;
;
![2A=-2D](https://tex.z-dn.net/?f=2A%3D-2D)
B is parallel to C and in same direction.
![B//C\\B=C\\](https://tex.z-dn.net/?f=B%2F%2FC%5C%5CB%3DC%5C%5C)
![0.5B=0.5C\\](https://tex.z-dn.net/?f=0.5B%3D0.5C%5C%5C)
![R= B-D;\\R= 0.5B+0.5B-D;\\R=0.5B+0.5C-D;\\R=0.5B+0.5C-2D+D;\\R=0.5B+0.5C+2A+D;](https://tex.z-dn.net/?f=R%3D%20B-D%3B%5C%5CR%3D%200.5B%2B0.5B-D%3B%5C%5CR%3D0.5B%2B0.5C-D%3B%5C%5CR%3D0.5B%2B0.5C-2D%2BD%3B%5C%5CR%3D0.5B%2B0.5C%2B2A%2BD%3B)
Using lens equation;
1/o + 1/i = 1/f; where o = Object distance, i = image distance (normally negative), f = focal length (normally negative)
Substituting;
1/o + 1/-30 = 1/-43 => 1/o = -1/43 + 1/30 = 0.01 => o = 1/0.01 = 99.23 cm
Therefore, the object should be place 99.23 cm from the lens.
Answer:
I think the answer is B. amount of energy present but I'm not 100% sure
Explanation: