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4 years ago

`

2 answers:

5 0

Time, obviously! Unless some extraterrestrial interference occurs, we have a LOT over time to figure out how to venture further into the vastness of space.

givi [52]4 years ago

4 0

Its time. Hope this helps :D

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A motorist drives north for 35.0 minutes at 85.0 kph. He then stops for 15.0 minutes. The motorist then drives 130.0 km in 2.0 h

o-na [289]

Answer:

A. 216.36 $\frac{km}{h}$

B. 96.56 $\frac{km}{h}$

Explanation:

Let $s_{1}$ be the distance in first part.

$s_{1}$ = velocity × time

$s_{1}$ = 85 × $\frac{35}{60}$

$s_{1}$ = 49.58 km

Let $s_{2}$ be the distance in first part.

$s_{2}$ = 130 km

Average velocity = $\frac{Total displacement}{Total time}$

When second leg of the trip is

A. Toward north

Average velocity = $\frac{[tex] s_{1} + s_{2}$ }{Total time} [/tex]

Average velocity = $\frac{130+49.58}{0.25+0.58}$

Average velocity =216.36 $\frac{km}{h}$

B. Toward south

Average velocity = $\frac{[tex] s_{1} - s_{2}$ }{Total time} [/tex]

Average velocity = $\frac{130-49.58}{0.25+0.58}$

Average velocity =96.56 $\frac{km}{h}$

3 0

3 years ago

What is kinetic friction?

Lunna [17]

Answer:

Kinetic friction is an inhibitory force that is present when a body or object begins to move. It should be noted that this force is in the opposite direction to the movement of the body that slides with respect to a surface and parallel to that surface.

In addition, this friction varies according to the surface characteristics and the material properties of the bodies that slide in this surface. Being quantified by the coefficient of kinetic friction $\mu_{K}$ , which is dimensionless.

4 0

4 years ago

Why is gasoline so flammable

Karo-lina-s [1.5K]

Flammable and combustible liquids themselves do not burn. It is the mixture of their vapours and air that burns. Gasoline, with a flashpoint of -40°C (-40°F), is a flammable liquid. Even at temperatures as low as -40°C (-40°F), it gives off enough vapour to form a burnable mixture in air.

Hope this helps

I looked this up

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8 0

4 years ago

Read 2 more answers

A car accelerates uniformly from rest to a speed of 7.6 m/s in 4.6 s. How far does the car travel in that time?

uysha [10]

Answer:

The car will travel a distance of 17.45 meters.

Explanation:

Given:

Initial velocity $(V_i)$ = 0

Final velocity $(V_f)$ = 7.6 m/s

Time taken = 4.6 s

Acceleration = (Final velocity - Initial Velocity )/time

$a=\frac{(V_f-Vi)}{t}= \frac{7.6-0}{4.6}=1.65\ ms^-2$

We have to calculate total distance traveled by the car.

Let the distance traveled be 'd'

Equation of motion:

$d=V_i(t)+\frac{at^2}{2}$

Plugging the values.

⇒ $d=V_i(t)+\frac{at^2}{2}$

⇒ $d=0+\frac{1.65*(4.6)^2}{2}$

⇒ $d=17.45\ m$

The car will travel a distance of 17.45 meters for the above case.

4 0

3 years ago

A certain spring stretches 3 cm when a load of 15 n is suspended from it. how much will the spring stretch if 30 n is suspended

Alik [6]

Initially, the spring stretches by 3 cm under a force of 15 N. From these data, we can find the value of the spring constant, given by Hook's law:
$k= \frac{F}{\Delta x}$
where F is the force applied, and $\Delta x$ is the stretch of the spring with respect to its equilibrium position. Using the data, we find
$k= \frac{15 N}{3.0 cm}=5.0 N/cm$

Now a force of 30 N is applied to the same spring, with constant k=5.0 N/cm. Using again Hook's law, we can find the new stretch of the spring:
$\Delta x = \frac{F}{k}= \frac{30 N}{5.0 N/cm}=6 cm$

4 0

3 years ago

Read 2 more answers